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How do you factor 2y squared plus 9y minus 2? - Answers

2y2 + 9y - 2 this will not factor using integers what is what most algebra teachers will tell you is 'prime'but ... make an equation ... 2y2 + 9y - 2 = 0use the quadratic formula to solvey = [-9 (+/-) sq rt (81 -4x2(-2))] / (2x2)y = [-9 (+/-) sq rt (97)] / (4) now separate thesey = [-9 + sq rt (97)] / (4)y = [-9 - sq rt (97)] / (4) rewrite as equal to zero(y - [-9 + sq rt (97)] / (4)) =0(y - [-9 - sq rt (97)] / (4)) = 0 apply zero product property in reverse(y - [-9 + sq rt (97)] / (4))(y - [-9 - sq rt (97)] / (4)) = 0these, as weird as they may look, are the factors.



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How do you factor 2y squared plus 9y minus 2? - Answers

https://math.answers.com/algebra/How_do_you_factor_2y_squared_plus_9y_minus_2

2y2 + 9y - 2 this will not factor using integers what is what most algebra teachers will tell you is 'prime'but ... make an equation ... 2y2 + 9y - 2 = 0use the quadratic formula to solvey = [-9 (+/-) sq rt (81 -4x2(-2))] / (2x2)y = [-9 (+/-) sq rt (97)] / (4) now separate thesey = [-9 + sq rt (97)] / (4)y = [-9 - sq rt (97)] / (4) rewrite as equal to zero(y - [-9 + sq rt (97)] / (4)) =0(y - [-9 - sq rt (97)] / (4)) = 0 apply zero product property in reverse(y - [-9 + sq rt (97)] / (4))(y - [-9 - sq rt (97)] / (4)) = 0these, as weird as they may look, are the factors.



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https://math.answers.com/algebra/How_do_you_factor_2y_squared_plus_9y_minus_2

How do you factor 2y squared plus 9y minus 2? - Answers

2y2 + 9y - 2 this will not factor using integers what is what most algebra teachers will tell you is 'prime'but ... make an equation ... 2y2 + 9y - 2 = 0use the quadratic formula to solvey = [-9 (+/-) sq rt (81 -4x2(-2))] / (2x2)y = [-9 (+/-) sq rt (97)] / (4) now separate thesey = [-9 + sq rt (97)] / (4)y = [-9 - sq rt (97)] / (4) rewrite as equal to zero(y - [-9 + sq rt (97)] / (4)) =0(y - [-9 - sq rt (97)] / (4)) = 0 apply zero product property in reverse(y - [-9 + sq rt (97)] / (4))(y - [-9 - sq rt (97)] / (4)) = 0these, as weird as they may look, are the factors.

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      2y2 + 9y - 2 this will not factor using integers what is what most algebra teachers will tell you is 'prime'but ... make an equation ... 2y2 + 9y - 2 = 0use the quadratic formula to solvey = [-9 (+/-) sq rt (81 -4x2(-2))] / (2x2)y = [-9 (+/-) sq rt (97)] / (4) now separate thesey = [-9 + sq rt (97)] / (4)y = [-9 - sq rt (97)] / (4) rewrite as equal to zero(y - [-9 + sq rt (97)] / (4)) =0(y - [-9 - sq rt (97)] / (4)) = 0 apply zero product property in reverse(y - [-9 + sq rt (97)] / (4))(y - [-9 - sq rt (97)] / (4)) = 0these, as weird as they may look, are the factors.
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