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How do you factor 6x2 - 7x - 3? - Answers

6x^2 - 7x - 3 Multiply the first and last coefficients: 6*(-3) = -18 Since this is negative you need two factor of 18 whose difference is the middle coefficient: -7. The factors are 2 and 9. The larger of these has the same sign as the middle coeff and the smaller has the opposite sign. Thus -9 and +2. So the expression can be written as = 1/6*(6x - 9)*(6x + 2) = 1/6*3*(2x - 3)*2*(3x + 1) = (2x - 3)*(3x + 1).



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How do you factor 6x2 - 7x - 3? - Answers

https://math.answers.com/algebra/How_do_you_factor_6x2_-_7x_-_3

6x^2 - 7x - 3 Multiply the first and last coefficients: 6*(-3) = -18 Since this is negative you need two factor of 18 whose difference is the middle coefficient: -7. The factors are 2 and 9. The larger of these has the same sign as the middle coeff and the smaller has the opposite sign. Thus -9 and +2. So the expression can be written as = 1/6*(6x - 9)*(6x + 2) = 1/6*3*(2x - 3)*2*(3x + 1) = (2x - 3)*(3x + 1).



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https://math.answers.com/algebra/How_do_you_factor_6x2_-_7x_-_3

How do you factor 6x2 - 7x - 3? - Answers

6x^2 - 7x - 3 Multiply the first and last coefficients: 6*(-3) = -18 Since this is negative you need two factor of 18 whose difference is the middle coefficient: -7. The factors are 2 and 9. The larger of these has the same sign as the middle coeff and the smaller has the opposite sign. Thus -9 and +2. So the expression can be written as = 1/6*(6x - 9)*(6x + 2) = 1/6*3*(2x - 3)*2*(3x + 1) = (2x - 3)*(3x + 1).

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      6x^2 - 7x - 3 Multiply the first and last coefficients: 6*(-3) = -18 Since this is negative you need two factor of 18 whose difference is the middle coefficient: -7. The factors are 2 and 9. The larger of these has the same sign as the middle coeff and the smaller has the opposite sign. Thus -9 and +2. So the expression can be written as = 1/6*(6x - 9)*(6x + 2) = 1/6*3*(2x - 3)*2*(3x + 1) = (2x - 3)*(3x + 1).

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