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https://math.answers.com/algebra/How_do_you_factor_8_minus_27x_cubed

How do you factor 8 minus 27x cubed? - Answers

Remember 8 = 2^(3) & 27x^(3) = (3x)^3 Hence 2^(3) - (3x)^3 is of the form x^(3) - y^(3) = ( x - y)(x^2 + xy + y^2) Hence 2^(3) - (3x)^(3) = ( 2 - 3y)(2^(2) + (2)(3y) + (3y)^(2)) => 2^(3) - (3y)^(3) = (2 - 3y)(4 + 6y + 9y^(2)) - Done!!!!!



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How do you factor 8 minus 27x cubed? - Answers

https://math.answers.com/algebra/How_do_you_factor_8_minus_27x_cubed

Remember 8 = 2^(3) & 27x^(3) = (3x)^3 Hence 2^(3) - (3x)^3 is of the form x^(3) - y^(3) = ( x - y)(x^2 + xy + y^2) Hence 2^(3) - (3x)^(3) = ( 2 - 3y)(2^(2) + (2)(3y) + (3y)^(2)) => 2^(3) - (3y)^(3) = (2 - 3y)(4 + 6y + 9y^(2)) - Done!!!!!



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https://math.answers.com/algebra/How_do_you_factor_8_minus_27x_cubed

How do you factor 8 minus 27x cubed? - Answers

Remember 8 = 2^(3) & 27x^(3) = (3x)^3 Hence 2^(3) - (3x)^3 is of the form x^(3) - y^(3) = ( x - y)(x^2 + xy + y^2) Hence 2^(3) - (3x)^(3) = ( 2 - 3y)(2^(2) + (2)(3y) + (3y)^(2)) => 2^(3) - (3y)^(3) = (2 - 3y)(4 + 6y + 9y^(2)) - Done!!!!!

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      Remember 8 = 2^(3) & 27x^(3) = (3x)^3 Hence 2^(3) - (3x)^3 is of the form x^(3) - y^(3) = ( x - y)(x^2 + xy + y^2) Hence 2^(3) - (3x)^(3) = ( 2 - 3y)(2^(2) + (2)(3y) + (3y)^(2)) => 2^(3) - (3y)^(3) = (2 - 3y)(4 + 6y + 9y^(2)) - Done!!!!!

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