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How do you find exponent N in 126 n12? - Answers

126 = n^12 12 = log(base n)126 Since log(base n)(126) = log 126/log n or log(base n)(126) = ln 126/ln n we write: 12 = ln 126/ln n 12 ln n = ln 126 ln n = ln 126/12 ln n = 0.4030234922 rewrite the natural logarithm showing base e (optional) log(base e)(n)= 0.4030234922 e^0.4030234922 = n Check e^0.4030234922 126 = (e^0.4030234922)^12 ? 126 = e^4.836281907 ? 126 = 126 True



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How do you find exponent N in 126 n12? - Answers

https://math.answers.com/algebra/How_do_you_find_exponent_N_in_126_n12

126 = n^12 12 = log(base n)126 Since log(base n)(126) = log 126/log n or log(base n)(126) = ln 126/ln n we write: 12 = ln 126/ln n 12 ln n = ln 126 ln n = ln 126/12 ln n = 0.4030234922 rewrite the natural logarithm showing base e (optional) log(base e)(n)= 0.4030234922 e^0.4030234922 = n Check e^0.4030234922 126 = (e^0.4030234922)^12 ? 126 = e^4.836281907 ? 126 = 126 True



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https://math.answers.com/algebra/How_do_you_find_exponent_N_in_126_n12

How do you find exponent N in 126 n12? - Answers

126 = n^12 12 = log(base n)126 Since log(base n)(126) = log 126/log n or log(base n)(126) = ln 126/ln n we write: 12 = ln 126/ln n 12 ln n = ln 126 ln n = ln 126/12 ln n = 0.4030234922 rewrite the natural logarithm showing base e (optional) log(base e)(n)= 0.4030234922 e^0.4030234922 = n Check e^0.4030234922 126 = (e^0.4030234922)^12 ? 126 = e^4.836281907 ? 126 = 126 True

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      126 = n^12 12 = log(base n)126 Since log(base n)(126) = log 126/log n or log(base n)(126) = ln 126/ln n we write: 12 = ln 126/ln n 12 ln n = ln 126 ln n = ln 126/12 ln n = 0.4030234922 rewrite the natural logarithm showing base e (optional) log(base e)(n)= 0.4030234922 e^0.4030234922 = n Check e^0.4030234922 126 = (e^0.4030234922)^12 ? 126 = e^4.836281907 ? 126 = 126 True

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