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How do you find the center and radius of x2 Y2 16? - Answers

You need to think of that equation in terms of the classic definition of a circle: (x - a)2 + (y - b)2 = r2 where a and b are the center of the circle, x and y are any point on it's circumference, and r is it's radius. In the case of the circle you're looking at: x2 + y2 = 16 You can re-express it like this: (x - 0)2 + (y - 0)2 = 42 So that circle has a center at the point (0, 0), and a radius of 4.



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How do you find the center and radius of x2 Y2 16? - Answers

https://math.answers.com/algebra/How_do_you_find_the_center_and_radius_of_x2_Y2_16

You need to think of that equation in terms of the classic definition of a circle: (x - a)2 + (y - b)2 = r2 where a and b are the center of the circle, x and y are any point on it's circumference, and r is it's radius. In the case of the circle you're looking at: x2 + y2 = 16 You can re-express it like this: (x - 0)2 + (y - 0)2 = 42 So that circle has a center at the point (0, 0), and a radius of 4.



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https://math.answers.com/algebra/How_do_you_find_the_center_and_radius_of_x2_Y2_16

How do you find the center and radius of x2 Y2 16? - Answers

You need to think of that equation in terms of the classic definition of a circle: (x - a)2 + (y - b)2 = r2 where a and b are the center of the circle, x and y are any point on it's circumference, and r is it's radius. In the case of the circle you're looking at: x2 + y2 = 16 You can re-express it like this: (x - 0)2 + (y - 0)2 = 42 So that circle has a center at the point (0, 0), and a radius of 4.

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      You need to think of that equation in terms of the classic definition of a circle: (x - a)2 + (y - b)2 = r2 where a and b are the center of the circle, x and y are any point on it's circumference, and r is it's radius. In the case of the circle you're looking at: x2 + y2 = 16 You can re-express it like this: (x - 0)2 + (y - 0)2 = 42 So that circle has a center at the point (0, 0), and a radius of 4.

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