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How do you find the max and min in a quadratic equation? - Answers

A quadratic function is of the form: f(x) = ax2 + bx + c where a ≠ 0 If a > 0 then the quadratic has a minimum but its maximum, asymptotically, is +∞. If a < 0 then the quadratic has a maximum but its minimum, asymptotically, is -∞. The extremum (whichever it is) is attained when x = -b/2a. The extreme value is f(-b/2a) = a*(-b/2a)2 + b(-b/2a) + c = b2/4a - b2/2a + c = -b2/4a + c



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How do you find the max and min in a quadratic equation? - Answers

https://math.answers.com/algebra/How_do_you_find_the_max_and_min_in_a_quadratic_equation

A quadratic function is of the form: f(x) = ax2 + bx + c where a ≠ 0 If a > 0 then the quadratic has a minimum but its maximum, asymptotically, is +∞. If a < 0 then the quadratic has a maximum but its minimum, asymptotically, is -∞. The extremum (whichever it is) is attained when x = -b/2a. The extreme value is f(-b/2a) = a*(-b/2a)2 + b(-b/2a) + c = b2/4a - b2/2a + c = -b2/4a + c



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https://math.answers.com/algebra/How_do_you_find_the_max_and_min_in_a_quadratic_equation

How do you find the max and min in a quadratic equation? - Answers

A quadratic function is of the form: f(x) = ax2 + bx + c where a ≠ 0 If a > 0 then the quadratic has a minimum but its maximum, asymptotically, is +∞. If a < 0 then the quadratic has a maximum but its minimum, asymptotically, is -∞. The extremum (whichever it is) is attained when x = -b/2a. The extreme value is f(-b/2a) = a*(-b/2a)2 + b(-b/2a) + c = b2/4a - b2/2a + c = -b2/4a + c

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      A quadratic function is of the form: f(x) = ax2 + bx + c where a ≠ 0 If a > 0 then the quadratic has a minimum but its maximum, asymptotically, is +∞. If a < 0 then the quadratic has a maximum but its minimum, asymptotically, is -∞. The extremum (whichever it is) is attained when x = -b/2a. The extreme value is f(-b/2a) = a*(-b/2a)2 + b(-b/2a) + c = b2/4a - b2/2a + c = -b2/4a + c

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