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How do you graph 2x plus 5y 10? - Answers
2x+5y=10is the same as5y=-2x+10Now divide both sides by 5y=-2/5x+2So the graph is a line with y intercept of 2 and slope of -2/5.Let's find at least 3 points in order to draw the graph of y = -(2/5)x + 2.y-intercept = 2 yields the point (0, 2)y = 0 yields the point (5, 0) which is the x-intercept.x = -1 yields the point (-1, 2.4)x = 1 yields the point (1, 1.6)..Now you can graph the line that passes through the points that you obtained.It's a straight from (0/2) to (5/0).
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How do you graph 2x plus 5y 10? - Answers
2x+5y=10is the same as5y=-2x+10Now divide both sides by 5y=-2/5x+2So the graph is a line with y intercept of 2 and slope of -2/5.Let's find at least 3 points in order to draw the graph of y = -(2/5)x + 2.y-intercept = 2 yields the point (0, 2)y = 0 yields the point (5, 0) which is the x-intercept.x = -1 yields the point (-1, 2.4)x = 1 yields the point (1, 1.6)..Now you can graph the line that passes through the points that you obtained.It's a straight from (0/2) to (5/0).
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How do you graph 2x plus 5y 10? - Answers
2x+5y=10is the same as5y=-2x+10Now divide both sides by 5y=-2/5x+2So the graph is a line with y intercept of 2 and slope of -2/5.Let's find at least 3 points in order to draw the graph of y = -(2/5)x + 2.y-intercept = 2 yields the point (0, 2)y = 0 yields the point (5, 0) which is the x-intercept.x = -1 yields the point (-1, 2.4)x = 1 yields the point (1, 1.6)..Now you can graph the line that passes through the points that you obtained.It's a straight from (0/2) to (5/0).
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- og:description2x+5y=10is the same as5y=-2x+10Now divide both sides by 5y=-2/5x+2So the graph is a line with y intercept of 2 and slope of -2/5.Let's find at least 3 points in order to draw the graph of y = -(2/5)x + 2.y-intercept = 2 yields the point (0, 2)y = 0 yields the point (5, 0) which is the x-intercept.x = -1 yields the point (-1, 2.4)x = 1 yields the point (1, 1.6)..Now you can graph the line that passes through the points that you obtained.It's a straight from (0/2) to (5/0).
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