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How do you graph y equals x2 2x 8? - Answers

y = x2 + 2x + 8 a = 1 > 0 the parabola opens upward, b = 2, c = 8 the y-intercept is (0, 8). axis of symmetry: x = -b/2a = -1 The axis of symmetry passes through x = -1, so we have the point (-2, 8) which is symmetrical to (0, 8). Let f(x) = y, and evaluate f(-1) to find the y-coordinate of the vertex. f(-1) = (-1)2 + 2(-1) + 8 = 7; vertex = (-1, 7). Since the parabola opens upward and the vertex lies on the second quadrant, there are no x-intercepts. Evaluate f(1) = (1)2 + 2(1) + 8 = 11; (1, 11) symmetrical to (-3, 11). Just plot the points and draw the parabola.



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How do you graph y equals x2 2x 8? - Answers

https://math.answers.com/algebra/How_do_you_graph_y_equals_x2_2x_8

y = x2 + 2x + 8 a = 1 > 0 the parabola opens upward, b = 2, c = 8 the y-intercept is (0, 8). axis of symmetry: x = -b/2a = -1 The axis of symmetry passes through x = -1, so we have the point (-2, 8) which is symmetrical to (0, 8). Let f(x) = y, and evaluate f(-1) to find the y-coordinate of the vertex. f(-1) = (-1)2 + 2(-1) + 8 = 7; vertex = (-1, 7). Since the parabola opens upward and the vertex lies on the second quadrant, there are no x-intercepts. Evaluate f(1) = (1)2 + 2(1) + 8 = 11; (1, 11) symmetrical to (-3, 11). Just plot the points and draw the parabola.



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https://math.answers.com/algebra/How_do_you_graph_y_equals_x2_2x_8

How do you graph y equals x2 2x 8? - Answers

y = x2 + 2x + 8 a = 1 > 0 the parabola opens upward, b = 2, c = 8 the y-intercept is (0, 8). axis of symmetry: x = -b/2a = -1 The axis of symmetry passes through x = -1, so we have the point (-2, 8) which is symmetrical to (0, 8). Let f(x) = y, and evaluate f(-1) to find the y-coordinate of the vertex. f(-1) = (-1)2 + 2(-1) + 8 = 7; vertex = (-1, 7). Since the parabola opens upward and the vertex lies on the second quadrant, there are no x-intercepts. Evaluate f(1) = (1)2 + 2(1) + 8 = 11; (1, 11) symmetrical to (-3, 11). Just plot the points and draw the parabola.

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      y = x2 + 2x + 8 a = 1 > 0 the parabola opens upward, b = 2, c = 8 the y-intercept is (0, 8). axis of symmetry: x = -b/2a = -1 The axis of symmetry passes through x = -1, so we have the point (-2, 8) which is symmetrical to (0, 8). Let f(x) = y, and evaluate f(-1) to find the y-coordinate of the vertex. f(-1) = (-1)2 + 2(-1) + 8 = 7; vertex = (-1, 7). Since the parabola opens upward and the vertex lies on the second quadrant, there are no x-intercepts. Evaluate f(1) = (1)2 + 2(1) + 8 = 11; (1, 11) symmetrical to (-3, 11). Just plot the points and draw the parabola.

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