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How do you put 7x 2y14 in a graph? - Answers

Restate the question: How do you graph 7x+2y=14? The easiest way to graph this equation is to find the intercepts. . . To find the y-intercept, let x=0: 7(0)+2y=14 <=> 2y=14 <=> 2y/2=14/2 <=> y=7, so mark the point (0,7) on the graph. To find the x-intercept, let y=0: 7x+2(0)=14 <=> 7x=14 <=> x=2, so mark (2,0) on the graph and draw a straight line through the 2 points. With a little practice, and if the numbers are 'nice', you can almost do this by just looking at the equation, or you can think of (0,_),(_,0). My students call this "googly eyes"!



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How do you put 7x 2y14 in a graph? - Answers

https://math.answers.com/algebra/How_do_you_put_7x_2y14_in_a_graph

Restate the question: How do you graph 7x+2y=14? The easiest way to graph this equation is to find the intercepts. . . To find the y-intercept, let x=0: 7(0)+2y=14 <=> 2y=14 <=> 2y/2=14/2 <=> y=7, so mark the point (0,7) on the graph. To find the x-intercept, let y=0: 7x+2(0)=14 <=> 7x=14 <=> x=2, so mark (2,0) on the graph and draw a straight line through the 2 points. With a little practice, and if the numbers are 'nice', you can almost do this by just looking at the equation, or you can think of (0,_),(_,0). My students call this "googly eyes"!



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https://math.answers.com/algebra/How_do_you_put_7x_2y14_in_a_graph

How do you put 7x 2y14 in a graph? - Answers

Restate the question: How do you graph 7x+2y=14? The easiest way to graph this equation is to find the intercepts. . . To find the y-intercept, let x=0: 7(0)+2y=14 <=> 2y=14 <=> 2y/2=14/2 <=> y=7, so mark the point (0,7) on the graph. To find the x-intercept, let y=0: 7x+2(0)=14 <=> 7x=14 <=> x=2, so mark (2,0) on the graph and draw a straight line through the 2 points. With a little practice, and if the numbers are 'nice', you can almost do this by just looking at the equation, or you can think of (0,_),(_,0). My students call this "googly eyes"!

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      Restate the question: How do you graph 7x+2y=14? The easiest way to graph this equation is to find the intercepts. . . To find the y-intercept, let x=0: 7(0)+2y=14 <=> 2y=14 <=> 2y/2=14/2 <=> y=7, so mark the point (0,7) on the graph. To find the x-intercept, let y=0: 7x+2(0)=14 <=> 7x=14 <=> x=2, so mark (2,0) on the graph and draw a straight line through the 2 points. With a little practice, and if the numbers are 'nice', you can almost do this by just looking at the equation, or you can think of (0,_),(_,0). My students call this "googly eyes"!

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