math.answers.com/algebra/How_do_you_sketch_the_graph_x_squared_plus_3x

Preview meta tags from the math.answers.com website.

Linked Hostnames

8

Thumbnail

Search Engine Appearance

Google

https://math.answers.com/algebra/How_do_you_sketch_the_graph_x_squared_plus_3x

How do you sketch the graph x squared plus 3x? - Answers

x^2+3x is a quadratic function that may be factored into x*(x+3), which means that the graph has zeroes at x = 0 and x = -3. Because x^2, the dominant term, is positive, it means that the graph will be sloping up at the edges. It will look like a parabola that crosses the x-axis at 0 and -3 and opens up. Thus, the equation of the axis of symmetry is x = -3/2 or -1.5, (which passes in the midway of the x-intercepts)), and the x-intercept of the vertex is -3/2. So replace x with -3/2 into the parabola's equation, and find the y-coordinate of the vertex, -9/4 or -2.25. So that you have the vertex and the x-intercepts points, but still they are not enough to draw the parabola Let x = 1, then y = 4. So you have two more points: (1, 4) and (-4, 4). Plot these points and draw the parabola that passes through them.



Bing

How do you sketch the graph x squared plus 3x? - Answers

https://math.answers.com/algebra/How_do_you_sketch_the_graph_x_squared_plus_3x

x^2+3x is a quadratic function that may be factored into x*(x+3), which means that the graph has zeroes at x = 0 and x = -3. Because x^2, the dominant term, is positive, it means that the graph will be sloping up at the edges. It will look like a parabola that crosses the x-axis at 0 and -3 and opens up. Thus, the equation of the axis of symmetry is x = -3/2 or -1.5, (which passes in the midway of the x-intercepts)), and the x-intercept of the vertex is -3/2. So replace x with -3/2 into the parabola's equation, and find the y-coordinate of the vertex, -9/4 or -2.25. So that you have the vertex and the x-intercepts points, but still they are not enough to draw the parabola Let x = 1, then y = 4. So you have two more points: (1, 4) and (-4, 4). Plot these points and draw the parabola that passes through them.



DuckDuckGo

https://math.answers.com/algebra/How_do_you_sketch_the_graph_x_squared_plus_3x

How do you sketch the graph x squared plus 3x? - Answers

x^2+3x is a quadratic function that may be factored into x*(x+3), which means that the graph has zeroes at x = 0 and x = -3. Because x^2, the dominant term, is positive, it means that the graph will be sloping up at the edges. It will look like a parabola that crosses the x-axis at 0 and -3 and opens up. Thus, the equation of the axis of symmetry is x = -3/2 or -1.5, (which passes in the midway of the x-intercepts)), and the x-intercept of the vertex is -3/2. So replace x with -3/2 into the parabola's equation, and find the y-coordinate of the vertex, -9/4 or -2.25. So that you have the vertex and the x-intercepts points, but still they are not enough to draw the parabola Let x = 1, then y = 4. So you have two more points: (1, 4) and (-4, 4). Plot these points and draw the parabola that passes through them.

  • General Meta Tags

    22
    • title
      How do you sketch the graph x squared plus 3x? - Answers
    • charset
      utf-8
    • Content-Type
      text/html; charset=utf-8
    • viewport
      minimum-scale=1, initial-scale=1, width=device-width, shrink-to-fit=no
    • X-UA-Compatible
      IE=edge,chrome=1
  • Open Graph Meta Tags

    7
    • og:image
      https://st.answers.com/html_test_assets/Answers_Blue.jpeg
    • og:image:width
      900
    • og:image:height
      900
    • og:site_name
      Answers
    • og:description
      x^2+3x is a quadratic function that may be factored into x*(x+3), which means that the graph has zeroes at x = 0 and x = -3. Because x^2, the dominant term, is positive, it means that the graph will be sloping up at the edges. It will look like a parabola that crosses the x-axis at 0 and -3 and opens up. Thus, the equation of the axis of symmetry is x = -3/2 or -1.5, (which passes in the midway of the x-intercepts)), and the x-intercept of the vertex is -3/2. So replace x with -3/2 into the parabola's equation, and find the y-coordinate of the vertex, -9/4 or -2.25. So that you have the vertex and the x-intercepts points, but still they are not enough to draw the parabola Let x = 1, then y = 4. So you have two more points: (1, 4) and (-4, 4). Plot these points and draw the parabola that passes through them.
  • Twitter Meta Tags

    1
    • twitter:card
      summary_large_image
  • Link Tags

    16
    • alternate
      https://www.answers.com/feed.rss
    • apple-touch-icon
      /icons/180x180.png
    • canonical
      https://math.answers.com/algebra/How_do_you_sketch_the_graph_x_squared_plus_3x
    • icon
      /favicon.svg
    • icon
      /icons/16x16.png

Links

59