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How many 3 letter combinations with 26 letters? - Answers
The first letter can be any one of 26. For each of these ...The second letter can be any one of the remaining 25. For each of these ...The third letter can be any one of the remaining 24.So the number of different 3-letter line-ups is (26! / 23!) = (26 x 25 x 24) = 15,600.That's the answer if you care about the sequence of the letters, i.e. if you call ABC and ACB different.If you don't care about the order of the 3 letters ... if ABC, ACB, BAC, BCA, CAB, and CBA are allthe same to you, then there are six ways to arrange each group of 3 different letters.Then the total number of different picks is [ 26! / (23! 6!) ] = (15,600/6) = 2,600 .
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How many 3 letter combinations with 26 letters? - Answers
The first letter can be any one of 26. For each of these ...The second letter can be any one of the remaining 25. For each of these ...The third letter can be any one of the remaining 24.So the number of different 3-letter line-ups is (26! / 23!) = (26 x 25 x 24) = 15,600.That's the answer if you care about the sequence of the letters, i.e. if you call ABC and ACB different.If you don't care about the order of the 3 letters ... if ABC, ACB, BAC, BCA, CAB, and CBA are allthe same to you, then there are six ways to arrange each group of 3 different letters.Then the total number of different picks is [ 26! / (23! 6!) ] = (15,600/6) = 2,600 .
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How many 3 letter combinations with 26 letters? - Answers
The first letter can be any one of 26. For each of these ...The second letter can be any one of the remaining 25. For each of these ...The third letter can be any one of the remaining 24.So the number of different 3-letter line-ups is (26! / 23!) = (26 x 25 x 24) = 15,600.That's the answer if you care about the sequence of the letters, i.e. if you call ABC and ACB different.If you don't care about the order of the 3 letters ... if ABC, ACB, BAC, BCA, CAB, and CBA are allthe same to you, then there are six ways to arrange each group of 3 different letters.Then the total number of different picks is [ 26! / (23! 6!) ] = (15,600/6) = 2,600 .
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- og:descriptionThe first letter can be any one of 26. For each of these ...The second letter can be any one of the remaining 25. For each of these ...The third letter can be any one of the remaining 24.So the number of different 3-letter line-ups is (26! / 23!) = (26 x 25 x 24) = 15,600.That's the answer if you care about the sequence of the letters, i.e. if you call ABC and ACB different.If you don't care about the order of the 3 letters ... if ABC, ACB, BAC, BCA, CAB, and CBA are allthe same to you, then there are six ways to arrange each group of 3 different letters.Then the total number of different picks is [ 26! / (23! 6!) ] = (15,600/6) = 2,600 .
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