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How do you factor a8-b8 completely? - Answers
a8 - b8 = ((a4)2 - (b4)2) [the difference of two squares] = (a4 + b4)(a4 - b4) = (a4 + b4)(a2 + b2)(a2 - b2) = (a4 + b4)(a2 + b2)(a + b)(a -b)
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How do you factor a8-b8 completely? - Answers
https://math.answers.com/basic-math/How_do_you_factor_a8-b8_completely
a8 - b8 = ((a4)2 - (b4)2) [the difference of two squares] = (a4 + b4)(a4 - b4) = (a4 + b4)(a2 + b2)(a2 - b2) = (a4 + b4)(a2 + b2)(a + b)(a -b)
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How do you factor a8-b8 completely? - Answers
a8 - b8 = ((a4)2 - (b4)2) [the difference of two squares] = (a4 + b4)(a4 - b4) = (a4 + b4)(a2 + b2)(a2 - b2) = (a4 + b4)(a2 + b2)(a + b)(a -b)
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