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How do you factor x2 - 5x - 14? - Answers

x^2 - 5x - 14 To factor Look for all the factors of '14' / They are 1,2,7,& 14. Of these factorts we need to select two numbers ,which added or subtracted com to '5'. The numbers are .2. & .7. Hence write up the brackets (x 2 )(x 7) Next ; to select the correct signs. We note that '14' is negative, so the two signs are different ; + & - . Where does the '+' & '-'- go . Since '5x' is minus(-) then the large number in the brackets is the minus(-). Hence ( x + 2)(x - 7) Done!!!!



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How do you factor x2 - 5x - 14? - Answers

https://math.answers.com/basic-math/How_do_you_factor_x2_-_5x_-_14

x^2 - 5x - 14 To factor Look for all the factors of '14' / They are 1,2,7,& 14. Of these factorts we need to select two numbers ,which added or subtracted com to '5'. The numbers are .2. & .7. Hence write up the brackets (x 2 )(x 7) Next ; to select the correct signs. We note that '14' is negative, so the two signs are different ; + & - . Where does the '+' & '-'- go . Since '5x' is minus(-) then the large number in the brackets is the minus(-). Hence ( x + 2)(x - 7) Done!!!!



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https://math.answers.com/basic-math/How_do_you_factor_x2_-_5x_-_14

How do you factor x2 - 5x - 14? - Answers

x^2 - 5x - 14 To factor Look for all the factors of '14' / They are 1,2,7,& 14. Of these factorts we need to select two numbers ,which added or subtracted com to '5'. The numbers are .2. & .7. Hence write up the brackets (x 2 )(x 7) Next ; to select the correct signs. We note that '14' is negative, so the two signs are different ; + & - . Where does the '+' & '-'- go . Since '5x' is minus(-) then the large number in the brackets is the minus(-). Hence ( x + 2)(x - 7) Done!!!!

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      x^2 - 5x - 14 To factor Look for all the factors of '14' / They are 1,2,7,& 14. Of these factorts we need to select two numbers ,which added or subtracted com to '5'. The numbers are .2. & .7. Hence write up the brackets (x 2 )(x 7) Next ; to select the correct signs. We note that '14' is negative, so the two signs are different ; + & - . Where does the '+' & '-'- go . Since '5x' is minus(-) then the large number in the brackets is the minus(-). Hence ( x + 2)(x - 7) Done!!!!

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