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https://math.answers.com/basic-math/How_do_you_write_0.489_in_standard_form

How do you write 0.489 in standard form? - Answers

To write 0.489 in standard form, you express it in the form of ( a \times 10^n ), where ( 1 \leq a < 10 ) and ( n ) is an integer. For 0.489, you can rewrite it as ( 4.89 \times 10^{-1} ) since moving the decimal point one place to the right increases the exponent by -1. Thus, the standard form of 0.489 is ( 4.89 \times 10^{-1} ).



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How do you write 0.489 in standard form? - Answers

https://math.answers.com/basic-math/How_do_you_write_0.489_in_standard_form

To write 0.489 in standard form, you express it in the form of ( a \times 10^n ), where ( 1 \leq a < 10 ) and ( n ) is an integer. For 0.489, you can rewrite it as ( 4.89 \times 10^{-1} ) since moving the decimal point one place to the right increases the exponent by -1. Thus, the standard form of 0.489 is ( 4.89 \times 10^{-1} ).



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https://math.answers.com/basic-math/How_do_you_write_0.489_in_standard_form

How do you write 0.489 in standard form? - Answers

To write 0.489 in standard form, you express it in the form of ( a \times 10^n ), where ( 1 \leq a < 10 ) and ( n ) is an integer. For 0.489, you can rewrite it as ( 4.89 \times 10^{-1} ) since moving the decimal point one place to the right increases the exponent by -1. Thus, the standard form of 0.489 is ( 4.89 \times 10^{-1} ).

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      To write 0.489 in standard form, you express it in the form of ( a \times 10^n ), where ( 1 \leq a < 10 ) and ( n ) is an integer. For 0.489, you can rewrite it as ( 4.89 \times 10^{-1} ) since moving the decimal point one place to the right increases the exponent by -1. Thus, the standard form of 0.489 is ( 4.89 \times 10^{-1} ).

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