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https://math.answers.com/calculus/Does_the_order_of_transformation_of_functions_matter

Does the order of transformation of functions matter? - Answers

Nope.* * * * *The above answer is so wrong!Suppose f and g are two transformations wheref(x) = 2x, andg(x) = x2Then f(g(x)) = f(x2) = 2x2Whileg(f(x)) = g(2x) = (2x)2=4x2Therefore f(g(x)) = g(f(x)) only when x = 0



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Does the order of transformation of functions matter? - Answers

https://math.answers.com/calculus/Does_the_order_of_transformation_of_functions_matter

Nope.* * * * *The above answer is so wrong!Suppose f and g are two transformations wheref(x) = 2x, andg(x) = x2Then f(g(x)) = f(x2) = 2x2Whileg(f(x)) = g(2x) = (2x)2=4x2Therefore f(g(x)) = g(f(x)) only when x = 0



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https://math.answers.com/calculus/Does_the_order_of_transformation_of_functions_matter

Does the order of transformation of functions matter? - Answers

Nope.* * * * *The above answer is so wrong!Suppose f and g are two transformations wheref(x) = 2x, andg(x) = x2Then f(g(x)) = f(x2) = 2x2Whileg(f(x)) = g(2x) = (2x)2=4x2Therefore f(g(x)) = g(f(x)) only when x = 0

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      Nope.* * * * *The above answer is so wrong!Suppose f and g are two transformations wheref(x) = 2x, andg(x) = x2Then f(g(x)) = f(x2) = 2x2Whileg(f(x)) = g(2x) = (2x)2=4x2Therefore f(g(x)) = g(f(x)) only when x = 0

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