math.answers.com/calculus/How_do_you_use_the_substitution_method
Preview meta tags from the math.answers.com website.
Linked Hostnames
9- 25 links tomath.answers.com
- 25 links towww.answers.com
- 2 links toqa.answers.com
- 1 link totwitter.com
- 1 link towww.facebook.com
- 1 link towww.instagram.com
- 1 link towww.pinterest.com
- 1 link towww.tiktok.com
Thumbnail

Search Engine Appearance
How do you use the substitution method? - Answers
When finding an antiderivative, substitution can be very helpful. In your integral expression, look for a term that, if you took the derivative and perhaps manipulated it a bit, would give you another term in the same equation. For example, if your integral is ∫tanxdx or ∫((sinx)/(cosx))dx , you can choose cosx as your arbitrary variable (often u or w). If u=cosx, du=-sinxdx. Therefore, your expression using u becomes -∫du/u. We know that the antiderivative of 1/u is ln (absolute value x) +C. So, our answer with u is -ln (abs. val. u) +C. But BE CAREFUL, this is not your final answer. You must plug in the value you originally designated as u. Therefore, the final answer is -ln (abs. val. cosx) +C, with C as an arbitrary constant.
Bing
How do you use the substitution method? - Answers
When finding an antiderivative, substitution can be very helpful. In your integral expression, look for a term that, if you took the derivative and perhaps manipulated it a bit, would give you another term in the same equation. For example, if your integral is ∫tanxdx or ∫((sinx)/(cosx))dx , you can choose cosx as your arbitrary variable (often u or w). If u=cosx, du=-sinxdx. Therefore, your expression using u becomes -∫du/u. We know that the antiderivative of 1/u is ln (absolute value x) +C. So, our answer with u is -ln (abs. val. u) +C. But BE CAREFUL, this is not your final answer. You must plug in the value you originally designated as u. Therefore, the final answer is -ln (abs. val. cosx) +C, with C as an arbitrary constant.
DuckDuckGo
How do you use the substitution method? - Answers
When finding an antiderivative, substitution can be very helpful. In your integral expression, look for a term that, if you took the derivative and perhaps manipulated it a bit, would give you another term in the same equation. For example, if your integral is ∫tanxdx or ∫((sinx)/(cosx))dx , you can choose cosx as your arbitrary variable (often u or w). If u=cosx, du=-sinxdx. Therefore, your expression using u becomes -∫du/u. We know that the antiderivative of 1/u is ln (absolute value x) +C. So, our answer with u is -ln (abs. val. u) +C. But BE CAREFUL, this is not your final answer. You must plug in the value you originally designated as u. Therefore, the final answer is -ln (abs. val. cosx) +C, with C as an arbitrary constant.
General Meta Tags
22- titleHow do you use the substitution method? - Answers
- charsetutf-8
- Content-Typetext/html; charset=utf-8
- viewportminimum-scale=1, initial-scale=1, width=device-width, shrink-to-fit=no
- X-UA-CompatibleIE=edge,chrome=1
Open Graph Meta Tags
7- og:imagehttps://st.answers.com/html_test_assets/Answers_Blue.jpeg
- og:image:width900
- og:image:height900
- og:site_nameAnswers
- og:descriptionWhen finding an antiderivative, substitution can be very helpful. In your integral expression, look for a term that, if you took the derivative and perhaps manipulated it a bit, would give you another term in the same equation. For example, if your integral is ∫tanxdx or ∫((sinx)/(cosx))dx , you can choose cosx as your arbitrary variable (often u or w). If u=cosx, du=-sinxdx. Therefore, your expression using u becomes -∫du/u. We know that the antiderivative of 1/u is ln (absolute value x) +C. So, our answer with u is -ln (abs. val. u) +C. But BE CAREFUL, this is not your final answer. You must plug in the value you originally designated as u. Therefore, the final answer is -ln (abs. val. cosx) +C, with C as an arbitrary constant.
Twitter Meta Tags
1- twitter:cardsummary_large_image
Link Tags
16- alternatehttps://www.answers.com/feed.rss
- apple-touch-icon/icons/180x180.png
- canonicalhttps://math.answers.com/calculus/How_do_you_use_the_substitution_method
- icon/favicon.svg
- icon/icons/16x16.png
Links
58- https://math.answers.com
- https://math.answers.com/calculus/8x_plus_30_equals_4x_plus_18_solve_for_x
- https://math.answers.com/calculus/Double_integral_of_x_siny_dx_dy
- https://math.answers.com/calculus/How_do_you_solve_3X_plus_7_equals_4X
- https://math.answers.com/calculus/How_do_you_use_the_substitution_method