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Log x plus 7 equals 1 plus Log x-1? - Answers

logx +7=1+log(x-1) 6=log(x-1)-logx 6=log[(x-1)/x] 10^6=(x-1)/x 1,000,000x=x-1 999,999x=-1 x=-1/999,999



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Log x plus 7 equals 1 plus Log x-1? - Answers

https://math.answers.com/calculus/Log_x_plus_7_equals_1_plus_Log_x-1

logx +7=1+log(x-1) 6=log(x-1)-logx 6=log[(x-1)/x] 10^6=(x-1)/x 1,000,000x=x-1 999,999x=-1 x=-1/999,999



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https://math.answers.com/calculus/Log_x_plus_7_equals_1_plus_Log_x-1

Log x plus 7 equals 1 plus Log x-1? - Answers

logx +7=1+log(x-1) 6=log(x-1)-logx 6=log[(x-1)/x] 10^6=(x-1)/x 1,000,000x=x-1 999,999x=-1 x=-1/999,999

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      logx +7=1+log(x-1) 6=log(x-1)-logx 6=log[(x-1)/x] 10^6=(x-1)/x 1,000,000x=x-1 999,999x=-1 x=-1/999,999

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