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https://math.answers.com/calculus/Solve_X_square_root_2_equals_4_-_7x

Solve X square root 2 equals 4 - 7x? - Answers

I understand your question to be this: x√2 = 4-7x So I would plus 7x to both sides to get this: x√2 + 7x = 4 Then take x out of the bracket to get this: x(√2 + 7) = 4 Finally divide both sides by (√2 + 7) to leave x on its on, and you should get something like this: x = 4/(√2 + 7)



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Solve X square root 2 equals 4 - 7x? - Answers

https://math.answers.com/calculus/Solve_X_square_root_2_equals_4_-_7x

I understand your question to be this: x√2 = 4-7x So I would plus 7x to both sides to get this: x√2 + 7x = 4 Then take x out of the bracket to get this: x(√2 + 7) = 4 Finally divide both sides by (√2 + 7) to leave x on its on, and you should get something like this: x = 4/(√2 + 7)



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https://math.answers.com/calculus/Solve_X_square_root_2_equals_4_-_7x

Solve X square root 2 equals 4 - 7x? - Answers

I understand your question to be this: x√2 = 4-7x So I would plus 7x to both sides to get this: x√2 + 7x = 4 Then take x out of the bracket to get this: x(√2 + 7) = 4 Finally divide both sides by (√2 + 7) to leave x on its on, and you should get something like this: x = 4/(√2 + 7)

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      I understand your question to be this: x√2 = 4-7x So I would plus 7x to both sides to get this: x√2 + 7x = 4 Then take x out of the bracket to get this: x(√2 + 7) = 4 Finally divide both sides by (√2 + 7) to leave x on its on, and you should get something like this: x = 4/(√2 + 7)

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