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A polygon has 14 diagonals how many sides does it have? - Answers

To determine the number of sides in a polygon with 14 diagonals, we can use the formula for the number of diagonals in a polygon: D = n(n-3)/2, where n is the number of sides. By setting D = 14 and solving for n, we get n(n-3)/2 = 14. Simplifying this equation, we find that n^2 - 3n - 28 = 0. Factoring this quadratic equation, we get (n-7)(n+4) = 0. Therefore, the polygon has either 7 or -4 sides. Since the number of sides cannot be negative, the polygon must have 7 sides.



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A polygon has 14 diagonals how many sides does it have? - Answers

https://math.answers.com/geometry/A_polygon_has_14_diagonals_how_many_sides_does_it_have

To determine the number of sides in a polygon with 14 diagonals, we can use the formula for the number of diagonals in a polygon: D = n(n-3)/2, where n is the number of sides. By setting D = 14 and solving for n, we get n(n-3)/2 = 14. Simplifying this equation, we find that n^2 - 3n - 28 = 0. Factoring this quadratic equation, we get (n-7)(n+4) = 0. Therefore, the polygon has either 7 or -4 sides. Since the number of sides cannot be negative, the polygon must have 7 sides.



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https://math.answers.com/geometry/A_polygon_has_14_diagonals_how_many_sides_does_it_have

A polygon has 14 diagonals how many sides does it have? - Answers

To determine the number of sides in a polygon with 14 diagonals, we can use the formula for the number of diagonals in a polygon: D = n(n-3)/2, where n is the number of sides. By setting D = 14 and solving for n, we get n(n-3)/2 = 14. Simplifying this equation, we find that n^2 - 3n - 28 = 0. Factoring this quadratic equation, we get (n-7)(n+4) = 0. Therefore, the polygon has either 7 or -4 sides. Since the number of sides cannot be negative, the polygon must have 7 sides.

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      To determine the number of sides in a polygon with 14 diagonals, we can use the formula for the number of diagonals in a polygon: D = n(n-3)/2, where n is the number of sides. By setting D = 14 and solving for n, we get n(n-3)/2 = 14. Simplifying this equation, we find that n^2 - 3n - 28 = 0. Factoring this quadratic equation, we get (n-7)(n+4) = 0. Therefore, the polygon has either 7 or -4 sides. Since the number of sides cannot be negative, the polygon must have 7 sides.

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