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https://math.answers.com/geometry/Area_of_an_isosceles_triangle

Area of an isosceles triangle? - Answers

1/2 the base times the height. If given only the length of equal sides and the angle formed between them, assuming side length 'l' and angle as 'x' square of 'l' multiplied by sine of x divided by 2 It is given by under root 3 divided by 4 multiplied by a2 where "a" is the length of the equal side



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Area of an isosceles triangle? - Answers

https://math.answers.com/geometry/Area_of_an_isosceles_triangle

1/2 the base times the height. If given only the length of equal sides and the angle formed between them, assuming side length 'l' and angle as 'x' square of 'l' multiplied by sine of x divided by 2 It is given by under root 3 divided by 4 multiplied by a2 where "a" is the length of the equal side



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https://math.answers.com/geometry/Area_of_an_isosceles_triangle

Area of an isosceles triangle? - Answers

1/2 the base times the height. If given only the length of equal sides and the angle formed between them, assuming side length 'l' and angle as 'x' square of 'l' multiplied by sine of x divided by 2 It is given by under root 3 divided by 4 multiplied by a2 where "a" is the length of the equal side

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      1/2 the base times the height. If given only the length of equal sides and the angle formed between them, assuming side length 'l' and angle as 'x' square of 'l' multiplied by sine of x divided by 2 It is given by under root 3 divided by 4 multiplied by a2 where "a" is the length of the equal side

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