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Common multiples of 2 8 12? - Answers

To find a common multiple of 2, 8, and 12, we need to look at their prime factorization (the stuff you multiply together to get those numbers). 2 is prime. 8 = 2*2*2. 12 = 2*2*3. So, if we want to have a number that is a common multiple of 2, 8, and 12, it must be composed of the greatest amount of each prime number that 2, 8, and 12 have. So, it must be at least 2*2*2 * 3 = 24. So any common multiple will be of the form 24 * k, where k is any integer. So for example: k=1, 2, 3, 4, ... 24, 48, 72, 96, etc...



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Common multiples of 2 8 12? - Answers

https://math.answers.com/geometry/Common_multiples_of_2_8_12

To find a common multiple of 2, 8, and 12, we need to look at their prime factorization (the stuff you multiply together to get those numbers). 2 is prime. 8 = 2*2*2. 12 = 2*2*3. So, if we want to have a number that is a common multiple of 2, 8, and 12, it must be composed of the greatest amount of each prime number that 2, 8, and 12 have. So, it must be at least 2*2*2 * 3 = 24. So any common multiple will be of the form 24 * k, where k is any integer. So for example: k=1, 2, 3, 4, ... 24, 48, 72, 96, etc...



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https://math.answers.com/geometry/Common_multiples_of_2_8_12

Common multiples of 2 8 12? - Answers

To find a common multiple of 2, 8, and 12, we need to look at their prime factorization (the stuff you multiply together to get those numbers). 2 is prime. 8 = 2*2*2. 12 = 2*2*3. So, if we want to have a number that is a common multiple of 2, 8, and 12, it must be composed of the greatest amount of each prime number that 2, 8, and 12 have. So, it must be at least 2*2*2 * 3 = 24. So any common multiple will be of the form 24 * k, where k is any integer. So for example: k=1, 2, 3, 4, ... 24, 48, 72, 96, etc...

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      To find a common multiple of 2, 8, and 12, we need to look at their prime factorization (the stuff you multiply together to get those numbers). 2 is prime. 8 = 2*2*2. 12 = 2*2*3. So, if we want to have a number that is a common multiple of 2, 8, and 12, it must be composed of the greatest amount of each prime number that 2, 8, and 12 have. So, it must be at least 2*2*2 * 3 = 24. So any common multiple will be of the form 24 * k, where k is any integer. So for example: k=1, 2, 3, 4, ... 24, 48, 72, 96, etc...

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