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https://math.answers.com/geometry/How_do_you_compute_the_diagonal_of_a_cube

How do you compute the diagonal of a cube? - Answers

If each cube side is of length s, then the diagonal of the BASE is from Pythagorean theorem sqrt ( s^2 + s^2) = sqrt (2) times s = 1.414s The height of the cube is s, so we use the theorem again using the base diagonal and height to get the cube diagonal: sqrt( (1.414s)^2 + s^2) = sqrt (3s^2) = sqrt(3) times s = 1.732s



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How do you compute the diagonal of a cube? - Answers

https://math.answers.com/geometry/How_do_you_compute_the_diagonal_of_a_cube

If each cube side is of length s, then the diagonal of the BASE is from Pythagorean theorem sqrt ( s^2 + s^2) = sqrt (2) times s = 1.414s The height of the cube is s, so we use the theorem again using the base diagonal and height to get the cube diagonal: sqrt( (1.414s)^2 + s^2) = sqrt (3s^2) = sqrt(3) times s = 1.732s



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https://math.answers.com/geometry/How_do_you_compute_the_diagonal_of_a_cube

How do you compute the diagonal of a cube? - Answers

If each cube side is of length s, then the diagonal of the BASE is from Pythagorean theorem sqrt ( s^2 + s^2) = sqrt (2) times s = 1.414s The height of the cube is s, so we use the theorem again using the base diagonal and height to get the cube diagonal: sqrt( (1.414s)^2 + s^2) = sqrt (3s^2) = sqrt(3) times s = 1.732s

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      If each cube side is of length s, then the diagonal of the BASE is from Pythagorean theorem sqrt ( s^2 + s^2) = sqrt (2) times s = 1.414s The height of the cube is s, so we use the theorem again using the base diagonal and height to get the cube diagonal: sqrt( (1.414s)^2 + s^2) = sqrt (3s^2) = sqrt(3) times s = 1.732s

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