math.answers.com/geometry/How_do_you_find_diagonals_in_a_polygon
Preview meta tags from the math.answers.com website.
Linked Hostnames
8- 34 links tomath.answers.com
- 18 links towww.answers.com
- 1 link totwitter.com
- 1 link towww.facebook.com
- 1 link towww.instagram.com
- 1 link towww.pinterest.com
- 1 link towww.tiktok.com
- 1 link towww.youtube.com
Thumbnail

Search Engine Appearance
How do you find diagonals in a polygon? - Answers
Suppose a polygon has n vertices (and sides). From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex. Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals. number of diagonals = n(n-3)/2
Bing
How do you find diagonals in a polygon? - Answers
Suppose a polygon has n vertices (and sides). From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex. Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals. number of diagonals = n(n-3)/2
DuckDuckGo
How do you find diagonals in a polygon? - Answers
Suppose a polygon has n vertices (and sides). From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex. Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals. number of diagonals = n(n-3)/2
General Meta Tags
22- titleHow do you find diagonals in a polygon? - Answers
- charsetutf-8
- Content-Typetext/html; charset=utf-8
- viewportminimum-scale=1, initial-scale=1, width=device-width, shrink-to-fit=no
- X-UA-CompatibleIE=edge,chrome=1
Open Graph Meta Tags
7- og:imagehttps://st.answers.com/html_test_assets/Answers_Blue.jpeg
- og:image:width900
- og:image:height900
- og:site_nameAnswers
- og:descriptionSuppose a polygon has n vertices (and sides). From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex. Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals. number of diagonals = n(n-3)/2
Twitter Meta Tags
1- twitter:cardsummary_large_image
Link Tags
16- alternatehttps://www.answers.com/feed.rss
- apple-touch-icon/icons/180x180.png
- canonicalhttps://math.answers.com/geometry/How_do_you_find_diagonals_in_a_polygon
- icon/favicon.svg
- icon/icons/16x16.png
Links
58- https://math.answers.com
- https://math.answers.com/geometry/Can_parallel_lines_be_a_different_size_but_still_be_parallel
- https://math.answers.com/geometry/Does_the_king_playing_card_has_line_of_symmetry
- https://math.answers.com/geometry/How_big_is_Belgium_in_square_kilometers
- https://math.answers.com/geometry/How_do_you_find_diagonals_in_a_polygon