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-3x squared equals 5 plus 3x? - Answers

-3x2 = 5 + 3x (add 3x2 to both sides)0 = 3x2 + 5 + 3x or3x2 + 3x + 5 = 0 (since the discriminant is less than zero, we have complex roots)x = [-3 ± √[(32 - 4(3)(5)]]/2(3)x = [-3 ± √(9 - 60)]/6x = (-3 ± √-51)/6x = (-3 ± i√51)/6x = (-3 + i√51)/6 = -1/2 + (√51/6)i orx = (-3 - i√51)/6 = -1/2 - (√51/6)i



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-3x squared equals 5 plus 3x? - Answers

https://math.answers.com/math-and-arithmetic/-3x_squared_equals_5_plus_3x

-3x2 = 5 + 3x (add 3x2 to both sides)0 = 3x2 + 5 + 3x or3x2 + 3x + 5 = 0 (since the discriminant is less than zero, we have complex roots)x = [-3 ± √[(32 - 4(3)(5)]]/2(3)x = [-3 ± √(9 - 60)]/6x = (-3 ± √-51)/6x = (-3 ± i√51)/6x = (-3 + i√51)/6 = -1/2 + (√51/6)i orx = (-3 - i√51)/6 = -1/2 - (√51/6)i



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https://math.answers.com/math-and-arithmetic/-3x_squared_equals_5_plus_3x

-3x squared equals 5 plus 3x? - Answers

-3x2 = 5 + 3x (add 3x2 to both sides)0 = 3x2 + 5 + 3x or3x2 + 3x + 5 = 0 (since the discriminant is less than zero, we have complex roots)x = [-3 ± √[(32 - 4(3)(5)]]/2(3)x = [-3 ± √(9 - 60)]/6x = (-3 ± √-51)/6x = (-3 ± i√51)/6x = (-3 + i√51)/6 = -1/2 + (√51/6)i orx = (-3 - i√51)/6 = -1/2 - (√51/6)i

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      -3x2 = 5 + 3x (add 3x2 to both sides)0 = 3x2 + 5 + 3x or3x2 + 3x + 5 = 0 (since the discriminant is less than zero, we have complex roots)x = [-3 ± √[(32 - 4(3)(5)]]/2(3)x = [-3 ± √(9 - 60)]/6x = (-3 ± √-51)/6x = (-3 ± i√51)/6x = (-3 + i√51)/6 = -1/2 + (√51/6)i orx = (-3 - i√51)/6 = -1/2 - (√51/6)i

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