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15x2-24x plus 9 divided by 3x-3? - Answers

15x2 - 24x + 9 = 3*(5x2 - 8x + 3) = 3*(5x2 - 5x - 3x + 3)= 3*[5x(x - 1) -3*(x - 1)] = 3*(5x - 3)*(x - 1) . . . . . (A) 3x - 3 = 3*(x - 1) . . . . . . . (B) So, (A) and (B) have 3*(x - 1) as common factors and cancelling these gives (A)/(B) = 5x - 3



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15x2-24x plus 9 divided by 3x-3? - Answers

https://math.answers.com/math-and-arithmetic/15x2-24x_plus_9_divided_by_3x-3

15x2 - 24x + 9 = 3*(5x2 - 8x + 3) = 3*(5x2 - 5x - 3x + 3)= 3*[5x(x - 1) -3*(x - 1)] = 3*(5x - 3)*(x - 1) . . . . . (A) 3x - 3 = 3*(x - 1) . . . . . . . (B) So, (A) and (B) have 3*(x - 1) as common factors and cancelling these gives (A)/(B) = 5x - 3



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https://math.answers.com/math-and-arithmetic/15x2-24x_plus_9_divided_by_3x-3

15x2-24x plus 9 divided by 3x-3? - Answers

15x2 - 24x + 9 = 3*(5x2 - 8x + 3) = 3*(5x2 - 5x - 3x + 3)= 3*[5x(x - 1) -3*(x - 1)] = 3*(5x - 3)*(x - 1) . . . . . (A) 3x - 3 = 3*(x - 1) . . . . . . . (B) So, (A) and (B) have 3*(x - 1) as common factors and cancelling these gives (A)/(B) = 5x - 3

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      15x2 - 24x + 9 = 3*(5x2 - 8x + 3) = 3*(5x2 - 5x - 3x + 3)= 3*[5x(x - 1) -3*(x - 1)] = 3*(5x - 3)*(x - 1) . . . . . (A) 3x - 3 = 3*(x - 1) . . . . . . . (B) So, (A) and (B) have 3*(x - 1) as common factors and cancelling these gives (A)/(B) = 5x - 3

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