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2xsquared plus 12x plus 1 equals 0 solve by completing the square? - Answers

2x2+12x+1 = 0 By dividing all terms in the quadratic equation by 2 will make completing the square easier to work out: x2+6x+0.5 = 0 (x+3)2+0.5 = 0 (x+3)2-9+0.5 = 0 (x+3)2-8.5 = 0 (x+3)2 = 8.5 x+3 = the square root of 8.5 x = -3 and plus or minus the square root of 8.5



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2xsquared plus 12x plus 1 equals 0 solve by completing the square? - Answers

https://math.answers.com/math-and-arithmetic/2xsquared_plus_12x_plus_1_equals_0_solve_by_completing_the_square

2x2+12x+1 = 0 By dividing all terms in the quadratic equation by 2 will make completing the square easier to work out: x2+6x+0.5 = 0 (x+3)2+0.5 = 0 (x+3)2-9+0.5 = 0 (x+3)2-8.5 = 0 (x+3)2 = 8.5 x+3 = the square root of 8.5 x = -3 and plus or minus the square root of 8.5



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https://math.answers.com/math-and-arithmetic/2xsquared_plus_12x_plus_1_equals_0_solve_by_completing_the_square

2xsquared plus 12x plus 1 equals 0 solve by completing the square? - Answers

2x2+12x+1 = 0 By dividing all terms in the quadratic equation by 2 will make completing the square easier to work out: x2+6x+0.5 = 0 (x+3)2+0.5 = 0 (x+3)2-9+0.5 = 0 (x+3)2-8.5 = 0 (x+3)2 = 8.5 x+3 = the square root of 8.5 x = -3 and plus or minus the square root of 8.5

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      2x2+12x+1 = 0 By dividing all terms in the quadratic equation by 2 will make completing the square easier to work out: x2+6x+0.5 = 0 (x+3)2+0.5 = 0 (x+3)2-9+0.5 = 0 (x+3)2-8.5 = 0 (x+3)2 = 8.5 x+3 = the square root of 8.5 x = -3 and plus or minus the square root of 8.5

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