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3 consecutive integers that have a sum of 267? - Answers

a+b+c=267 simplify to one var x+(x+1)+(x+2)=267 x+x+1+x+2=267 3x+3=267 3x+3-3=267-3 3x=264 3x/3=264/3 x=88 therefore a=88 b=89 c=90

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3 consecutive integers that have a sum of 267? - Answers

https://math.answers.com/math-and-arithmetic/3_consecutive_integers_that_have_a_sum_of_267

a+b+c=267 simplify to one var x+(x+1)+(x+2)=267 x+x+1+x+2=267 3x+3=267 3x+3-3=267-3 3x=264 3x/3=264/3 x=88 therefore a=88 b=89 c=90

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https://math.answers.com/math-and-arithmetic/3_consecutive_integers_that_have_a_sum_of_267

3 consecutive integers that have a sum of 267? - Answers

a+b+c=267 simplify to one var x+(x+1)+(x+2)=267 x+x+1+x+2=267 3x+3=267 3x+3-3=267-3 3x=264 3x/3=264/3 x=88 therefore a=88 b=89 c=90

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  a+b+c=267 simplify to one var x+(x+1)+(x+2)=267 x+x+1+x+2=267 3x+3=267 3x+3-3=267-3 3x=264 3x/3=264/3 x=88 therefore a=88 b=89 c=90
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