math.answers.com/math-and-arithmetic/475_exceeds_five_times_a_number_by_85

Preview meta tags from the math.answers.com website.

Linked Hostnames

8

Thumbnail

Search Engine Appearance

Google

https://math.answers.com/math-and-arithmetic/475_exceeds_five_times_a_number_by_85

475 exceeds five times a number by 85? - Answers

Easiest way to figure this out is to re-state, in algebraic form, your original question.It might take a bit to think about what the question is asking, you know that you will have a variable (x) and it will by multiplied by 5. So, you have 5x.You have 475 exceeding 5x + 85, hmmm, does this fit the original question? YUP! okay, you need an equation, therefore, you can take the word "exceeding" and change that to an equals sign.Now, you have 475 = 5x + 85. Does this re-state your original question. Yup! Ta Da! we have ourselves an equation! Now we solve for x.To isolate x, first subtract 85 from both sides of the equation, to get 475 - 85 = 5x + (85-85).Now you have 390 = 5xDivide both sides by 5, to get 390 ÷ 5 = (5 ÷ 5)xnow you have your solution, because you have isolated x on one side of the equation. That solution would be: x = 78.



Bing

475 exceeds five times a number by 85? - Answers

https://math.answers.com/math-and-arithmetic/475_exceeds_five_times_a_number_by_85

Easiest way to figure this out is to re-state, in algebraic form, your original question.It might take a bit to think about what the question is asking, you know that you will have a variable (x) and it will by multiplied by 5. So, you have 5x.You have 475 exceeding 5x + 85, hmmm, does this fit the original question? YUP! okay, you need an equation, therefore, you can take the word "exceeding" and change that to an equals sign.Now, you have 475 = 5x + 85. Does this re-state your original question. Yup! Ta Da! we have ourselves an equation! Now we solve for x.To isolate x, first subtract 85 from both sides of the equation, to get 475 - 85 = 5x + (85-85).Now you have 390 = 5xDivide both sides by 5, to get 390 ÷ 5 = (5 ÷ 5)xnow you have your solution, because you have isolated x on one side of the equation. That solution would be: x = 78.



DuckDuckGo

https://math.answers.com/math-and-arithmetic/475_exceeds_five_times_a_number_by_85

475 exceeds five times a number by 85? - Answers

Easiest way to figure this out is to re-state, in algebraic form, your original question.It might take a bit to think about what the question is asking, you know that you will have a variable (x) and it will by multiplied by 5. So, you have 5x.You have 475 exceeding 5x + 85, hmmm, does this fit the original question? YUP! okay, you need an equation, therefore, you can take the word "exceeding" and change that to an equals sign.Now, you have 475 = 5x + 85. Does this re-state your original question. Yup! Ta Da! we have ourselves an equation! Now we solve for x.To isolate x, first subtract 85 from both sides of the equation, to get 475 - 85 = 5x + (85-85).Now you have 390 = 5xDivide both sides by 5, to get 390 ÷ 5 = (5 ÷ 5)xnow you have your solution, because you have isolated x on one side of the equation. That solution would be: x = 78.

  • General Meta Tags

    22
    • title
      475 exceeds five times a number by 85? - Answers
    • charset
      utf-8
    • Content-Type
      text/html; charset=utf-8
    • viewport
      minimum-scale=1, initial-scale=1, width=device-width, shrink-to-fit=no
    • X-UA-Compatible
      IE=edge,chrome=1

  • Open Graph Meta Tags

    7
    • og:image
      https://st.answers.com/html_test_assets/Answers_Blue.jpeg
    • og:image:width
      900
    • og:image:height
      900
    • og:site_name
      Answers
    • og:description
      Easiest way to figure this out is to re-state, in algebraic form, your original question.It might take a bit to think about what the question is asking, you know that you will have a variable (x) and it will by multiplied by 5. So, you have 5x.You have 475 exceeding 5x + 85, hmmm, does this fit the original question? YUP! okay, you need an equation, therefore, you can take the word "exceeding" and change that to an equals sign.Now, you have 475 = 5x + 85. Does this re-state your original question. Yup! Ta Da! we have ourselves an equation! Now we solve for x.To isolate x, first subtract 85 from both sides of the equation, to get 475 - 85 = 5x + (85-85).Now you have 390 = 5xDivide both sides by 5, to get 390 ÷ 5 = (5 ÷ 5)xnow you have your solution, because you have isolated x on one side of the equation. That solution would be: x = 78.

  • Twitter Meta Tags

    1
    • twitter:card
      summary_large_image

  • Link Tags

    16
    • alternate
      https://www.answers.com/feed.rss
    • apple-touch-icon
      /icons/180x180.png
    • canonical
      https://math.answers.com/math-and-arithmetic/475_exceeds_five_times_a_number_by_85
    • icon
      /favicon.svg
    • icon
      /icons/16x16.png

Links

58