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4 faces 6 edges 6 vertices? - Answers

The above numbers do not satisfy the Euler characteristic (Faces + Vertices = Edges + 2) and so it is not a simply connected polyhedron.



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4 faces 6 edges 6 vertices? - Answers

https://math.answers.com/math-and-arithmetic/4_faces_6_edges_6_vertices

The above numbers do not satisfy the Euler characteristic (Faces + Vertices = Edges + 2) and so it is not a simply connected polyhedron.



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https://math.answers.com/math-and-arithmetic/4_faces_6_edges_6_vertices

4 faces 6 edges 6 vertices? - Answers

The above numbers do not satisfy the Euler characteristic (Faces + Vertices = Edges + 2) and so it is not a simply connected polyhedron.

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