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https://math.answers.com/math-and-arithmetic/A-mixture-of-650-nails-costs-$4350-if-some-of-the-nails-cost-5-cents-a-piece-and-therest-costs-7-cents-a-piece-how-many-of-each-are-there

A mixture of 650 nails costs $43.50. If some of the nails cost 5 cents a piece, and therest costs 7 cents a piece, how many of each are there? - Answers

So the total number of nails is 650, therefore: X + Y = 650, and 5X + 7Y = 4350 First we can solve the first equation for Y: Y = 650-X Now that we know the relationship between X and Y, we can solve for one of them by substituting that value into the other equation. : 5X + 7Y = 4350 5X + 7(650-X) = 4350 5X + 4550 - 7X = 4350 -2X + 4550 = 4350 -2X=-200 X=100 Since Y = 650-X, Y = 550. If we plug those numbers into our original equations then we can verify the solution: 7(550) + 5(100) = 4350. (550) + (100) = 650



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A mixture of 650 nails costs $43.50. If some of the nails cost 5 cents a piece, and therest costs 7 cents a piece, how many of each are there? - Answers

https://math.answers.com/math-and-arithmetic/A-mixture-of-650-nails-costs-$4350-if-some-of-the-nails-cost-5-cents-a-piece-and-therest-costs-7-cents-a-piece-how-many-of-each-are-there

So the total number of nails is 650, therefore: X + Y = 650, and 5X + 7Y = 4350 First we can solve the first equation for Y: Y = 650-X Now that we know the relationship between X and Y, we can solve for one of them by substituting that value into the other equation. : 5X + 7Y = 4350 5X + 7(650-X) = 4350 5X + 4550 - 7X = 4350 -2X + 4550 = 4350 -2X=-200 X=100 Since Y = 650-X, Y = 550. If we plug those numbers into our original equations then we can verify the solution: 7(550) + 5(100) = 4350. (550) + (100) = 650



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https://math.answers.com/math-and-arithmetic/A-mixture-of-650-nails-costs-$4350-if-some-of-the-nails-cost-5-cents-a-piece-and-therest-costs-7-cents-a-piece-how-many-of-each-are-there

A mixture of 650 nails costs $43.50. If some of the nails cost 5 cents a piece, and therest costs 7 cents a piece, how many of each are there? - Answers

So the total number of nails is 650, therefore: X + Y = 650, and 5X + 7Y = 4350 First we can solve the first equation for Y: Y = 650-X Now that we know the relationship between X and Y, we can solve for one of them by substituting that value into the other equation. : 5X + 7Y = 4350 5X + 7(650-X) = 4350 5X + 4550 - 7X = 4350 -2X + 4550 = 4350 -2X=-200 X=100 Since Y = 650-X, Y = 550. If we plug those numbers into our original equations then we can verify the solution: 7(550) + 5(100) = 4350. (550) + (100) = 650

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      So the total number of nails is 650, therefore: X + Y = 650, and 5X + 7Y = 4350 First we can solve the first equation for Y: Y = 650-X Now that we know the relationship between X and Y, we can solve for one of them by substituting that value into the other equation. : 5X + 7Y = 4350 5X + 7(650-X) = 4350 5X + 4550 - 7X = 4350 -2X + 4550 = 4350 -2X=-200 X=100 Since Y = 650-X, Y = 550. If we plug those numbers into our original equations then we can verify the solution: 7(550) + 5(100) = 4350. (550) + (100) = 650

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