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AC equals AB plus BC? - Answers

(B/C) + (B/A) = 1 (1/B) = (1/A) + (1/C) B = AC/(A + C) This is the familiar lensmakers formula, or two resistors or inductors in parallel, or two capacitors in series. If 'A', 'B', and 'C' are supposed to be the vertices of a triangle, then the triangle is degenerate. It looks just like a straight line with the letters 'A' and 'C' at its ends and the letter 'B' sticking out somewhere between them for no apparent reason.



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AC equals AB plus BC? - Answers

https://math.answers.com/math-and-arithmetic/AC_equals_AB_plus_BC

(B/C) + (B/A) = 1 (1/B) = (1/A) + (1/C) B = AC/(A + C) This is the familiar lensmakers formula, or two resistors or inductors in parallel, or two capacitors in series. If 'A', 'B', and 'C' are supposed to be the vertices of a triangle, then the triangle is degenerate. It looks just like a straight line with the letters 'A' and 'C' at its ends and the letter 'B' sticking out somewhere between them for no apparent reason.



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https://math.answers.com/math-and-arithmetic/AC_equals_AB_plus_BC

AC equals AB plus BC? - Answers

(B/C) + (B/A) = 1 (1/B) = (1/A) + (1/C) B = AC/(A + C) This is the familiar lensmakers formula, or two resistors or inductors in parallel, or two capacitors in series. If 'A', 'B', and 'C' are supposed to be the vertices of a triangle, then the triangle is degenerate. It looks just like a straight line with the letters 'A' and 'C' at its ends and the letter 'B' sticking out somewhere between them for no apparent reason.

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      (B/C) + (B/A) = 1 (1/B) = (1/A) + (1/C) B = AC/(A + C) This is the familiar lensmakers formula, or two resistors or inductors in parallel, or two capacitors in series. If 'A', 'B', and 'C' are supposed to be the vertices of a triangle, then the triangle is degenerate. It looks just like a straight line with the letters 'A' and 'C' at its ends and the letter 'B' sticking out somewhere between them for no apparent reason.

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