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https://math.answers.com/math-and-arithmetic/All_the_combinations_you_can_make_out_of_1234567890_with_2_numbers

All the combinations you can make out of 1234567890 with 2 numbers? - Answers

If there are no restrictions on the 'combinations' then there are ten choices for the first digit and ten for the second: 10 x 10. (This implies possibilities such as 22 and 77.) If the digits must be different in each combination then the number of combinations taking two at a time from ten is C(10,2) = 10!/( 2! ( 10 - 2 )! ) = 45.



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All the combinations you can make out of 1234567890 with 2 numbers? - Answers

https://math.answers.com/math-and-arithmetic/All_the_combinations_you_can_make_out_of_1234567890_with_2_numbers

If there are no restrictions on the 'combinations' then there are ten choices for the first digit and ten for the second: 10 x 10. (This implies possibilities such as 22 and 77.) If the digits must be different in each combination then the number of combinations taking two at a time from ten is C(10,2) = 10!/( 2! ( 10 - 2 )! ) = 45.



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https://math.answers.com/math-and-arithmetic/All_the_combinations_you_can_make_out_of_1234567890_with_2_numbers

All the combinations you can make out of 1234567890 with 2 numbers? - Answers

If there are no restrictions on the 'combinations' then there are ten choices for the first digit and ten for the second: 10 x 10. (This implies possibilities such as 22 and 77.) If the digits must be different in each combination then the number of combinations taking two at a time from ten is C(10,2) = 10!/( 2! ( 10 - 2 )! ) = 45.

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      If there are no restrictions on the 'combinations' then there are ten choices for the first digit and ten for the second: 10 x 10. (This implies possibilities such as 22 and 77.) If the digits must be different in each combination then the number of combinations taking two at a time from ten is C(10,2) = 10!/( 2! ( 10 - 2 )! ) = 45.

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