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Are the diagonals of a square are never perpendicular? - Answers

The diagonals of a square are always perpendicular. Proof: Without loss of generality, assume the square has side length 1 and one vertex is at the origin. The square ABCD is given by: A = (0,0) , B = (1,0) , C = (1,1) , D = (0,1) The diagonals are d1=AC and d2=BD. Finding equations for each of them yields d1 = x d2 = 1-x (you can double check this) So, the relative slopes are 1 and -1. Since their product is -1, they are perpendicular.



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Are the diagonals of a square are never perpendicular? - Answers

https://math.answers.com/math-and-arithmetic/Are_the_diagonals_of_a_square_are_never_perpendicular

The diagonals of a square are always perpendicular. Proof: Without loss of generality, assume the square has side length 1 and one vertex is at the origin. The square ABCD is given by: A = (0,0) , B = (1,0) , C = (1,1) , D = (0,1) The diagonals are d1=AC and d2=BD. Finding equations for each of them yields d1 = x d2 = 1-x (you can double check this) So, the relative slopes are 1 and -1. Since their product is -1, they are perpendicular.



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https://math.answers.com/math-and-arithmetic/Are_the_diagonals_of_a_square_are_never_perpendicular

Are the diagonals of a square are never perpendicular? - Answers

The diagonals of a square are always perpendicular. Proof: Without loss of generality, assume the square has side length 1 and one vertex is at the origin. The square ABCD is given by: A = (0,0) , B = (1,0) , C = (1,1) , D = (0,1) The diagonals are d1=AC and d2=BD. Finding equations for each of them yields d1 = x d2 = 1-x (you can double check this) So, the relative slopes are 1 and -1. Since their product is -1, they are perpendicular.

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      The diagonals of a square are always perpendicular. Proof: Without loss of generality, assume the square has side length 1 and one vertex is at the origin. The square ABCD is given by: A = (0,0) , B = (1,0) , C = (1,1) , D = (0,1) The diagonals are d1=AC and d2=BD. Finding equations for each of them yields d1 = x d2 = 1-x (you can double check this) So, the relative slopes are 1 and -1. Since their product is -1, they are perpendicular.

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