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https://math.answers.com/math-and-arithmetic/Can_8m_4m_and_2m_make_a_right_triangle

Can 8m 4m and 2m make a right triangle? - Answers

To determine if the lengths 8m, 4m, and 2m can form a right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Here, the longest side is 8m. Calculating, we find that (8^2 = 64) and (4^2 + 2^2 = 16 + 4 = 20), which does not equal 64. Therefore, 8m, 4m, and 2m cannot form a right triangle.



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Can 8m 4m and 2m make a right triangle? - Answers

https://math.answers.com/math-and-arithmetic/Can_8m_4m_and_2m_make_a_right_triangle

To determine if the lengths 8m, 4m, and 2m can form a right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Here, the longest side is 8m. Calculating, we find that (8^2 = 64) and (4^2 + 2^2 = 16 + 4 = 20), which does not equal 64. Therefore, 8m, 4m, and 2m cannot form a right triangle.



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https://math.answers.com/math-and-arithmetic/Can_8m_4m_and_2m_make_a_right_triangle

Can 8m 4m and 2m make a right triangle? - Answers

To determine if the lengths 8m, 4m, and 2m can form a right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Here, the longest side is 8m. Calculating, we find that (8^2 = 64) and (4^2 + 2^2 = 16 + 4 = 20), which does not equal 64. Therefore, 8m, 4m, and 2m cannot form a right triangle.

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      To determine if the lengths 8m, 4m, and 2m can form a right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Here, the longest side is 8m. Calculating, we find that (8^2 = 64) and (4^2 + 2^2 = 16 + 4 = 20), which does not equal 64. Therefore, 8m, 4m, and 2m cannot form a right triangle.

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