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Can covariance be negative? - Answers

I'd be inclined to say no, Im looking for the answer myself. But if you have Cov(A-B,A+B)=Cov(A,A)-Cov(B,B)-Cov(B,A)+Cov(A,B), then the last two will cancel but if Var(B)>Var(A) then we would get a negative covariance. [Cov(A,A)=Var(A)] So it looks possible because as far as I know there is no squaring of the coefficeients when you bring them out of the covariance so a negative answer is entirely possible.



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Can covariance be negative? - Answers

https://math.answers.com/math-and-arithmetic/Can_covariance_be_negative

I'd be inclined to say no, Im looking for the answer myself. But if you have Cov(A-B,A+B)=Cov(A,A)-Cov(B,B)-Cov(B,A)+Cov(A,B), then the last two will cancel but if Var(B)>Var(A) then we would get a negative covariance. [Cov(A,A)=Var(A)] So it looks possible because as far as I know there is no squaring of the coefficeients when you bring them out of the covariance so a negative answer is entirely possible.



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https://math.answers.com/math-and-arithmetic/Can_covariance_be_negative

Can covariance be negative? - Answers

I'd be inclined to say no, Im looking for the answer myself. But if you have Cov(A-B,A+B)=Cov(A,A)-Cov(B,B)-Cov(B,A)+Cov(A,B), then the last two will cancel but if Var(B)>Var(A) then we would get a negative covariance. [Cov(A,A)=Var(A)] So it looks possible because as far as I know there is no squaring of the coefficeients when you bring them out of the covariance so a negative answer is entirely possible.

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      I'd be inclined to say no, Im looking for the answer myself. But if you have Cov(A-B,A+B)=Cov(A,A)-Cov(B,B)-Cov(B,A)+Cov(A,B), then the last two will cancel but if Var(B)>Var(A) then we would get a negative covariance. [Cov(A,A)=Var(A)] So it looks possible because as far as I know there is no squaring of the coefficeients when you bring them out of the covariance so a negative answer is entirely possible.

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