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Can you factor x2-6x plus 18? - Answers

x^2 - 6x + 18. This looks tempting to factor by guessing. We want to factor into the form (1x + a) * (1x + b) + c We guess that both x's have a scalar constant of 1, because x^2 has a scalar constant of 1 in the expanded form. This doesn't have to be the case, but it is a convenient assumption to make. We want a and b such that (a + b) = -6. A good choice for this is a = -3, b = -3 a * b = 9, so we need c to cover the distance between 9 and 18. c = 9 So we have: (x - 3) * (x - 3) + 9 Double checking to make sure we did everything right: x ^ 2 - 3x - 3x + 9 + 9 x^2 - 6x + 18 You can also complete the square, if you prefer.



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Can you factor x2-6x plus 18? - Answers

https://math.answers.com/math-and-arithmetic/Can_you_factor_x2-6x_plus_18

x^2 - 6x + 18. This looks tempting to factor by guessing. We want to factor into the form (1x + a) * (1x + b) + c We guess that both x's have a scalar constant of 1, because x^2 has a scalar constant of 1 in the expanded form. This doesn't have to be the case, but it is a convenient assumption to make. We want a and b such that (a + b) = -6. A good choice for this is a = -3, b = -3 a * b = 9, so we need c to cover the distance between 9 and 18. c = 9 So we have: (x - 3) * (x - 3) + 9 Double checking to make sure we did everything right: x ^ 2 - 3x - 3x + 9 + 9 x^2 - 6x + 18 You can also complete the square, if you prefer.



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https://math.answers.com/math-and-arithmetic/Can_you_factor_x2-6x_plus_18

Can you factor x2-6x plus 18? - Answers

x^2 - 6x + 18. This looks tempting to factor by guessing. We want to factor into the form (1x + a) * (1x + b) + c We guess that both x's have a scalar constant of 1, because x^2 has a scalar constant of 1 in the expanded form. This doesn't have to be the case, but it is a convenient assumption to make. We want a and b such that (a + b) = -6. A good choice for this is a = -3, b = -3 a * b = 9, so we need c to cover the distance between 9 and 18. c = 9 So we have: (x - 3) * (x - 3) + 9 Double checking to make sure we did everything right: x ^ 2 - 3x - 3x + 9 + 9 x^2 - 6x + 18 You can also complete the square, if you prefer.

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      x^2 - 6x + 18. This looks tempting to factor by guessing. We want to factor into the form (1x + a) * (1x + b) + c We guess that both x's have a scalar constant of 1, because x^2 has a scalar constant of 1 in the expanded form. This doesn't have to be the case, but it is a convenient assumption to make. We want a and b such that (a + b) = -6. A good choice for this is a = -3, b = -3 a * b = 9, so we need c to cover the distance between 9 and 18. c = 9 So we have: (x - 3) * (x - 3) + 9 Double checking to make sure we did everything right: x ^ 2 - 3x - 3x + 9 + 9 x^2 - 6x + 18 You can also complete the square, if you prefer.

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