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Can you replace a capacitor of two different sizes? - Answers

Not sure what you are asking.There are two formulae for working out equivalent capacitance:Two capacitors in parallelThe equivalent single capacitance is the sum of the two capacitors: Ce = C1 + C2Two capacitors in seriesThe equivalent single capacitance is the reciprocal of the sum of the reciprocals of the two capacitors: 1/Ce = 1/C1 + 1/C2⇒ Ce = C1C2/(C1+C2)So you can replace two capacitors by a single one, or a single one by two.



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Can you replace a capacitor of two different sizes? - Answers

https://math.answers.com/math-and-arithmetic/Can_you_replace_a_capacitor_of_two_different_sizes

Not sure what you are asking.There are two formulae for working out equivalent capacitance:Two capacitors in parallelThe equivalent single capacitance is the sum of the two capacitors: Ce = C1 + C2Two capacitors in seriesThe equivalent single capacitance is the reciprocal of the sum of the reciprocals of the two capacitors: 1/Ce = 1/C1 + 1/C2⇒ Ce = C1C2/(C1+C2)So you can replace two capacitors by a single one, or a single one by two.



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https://math.answers.com/math-and-arithmetic/Can_you_replace_a_capacitor_of_two_different_sizes

Can you replace a capacitor of two different sizes? - Answers

Not sure what you are asking.There are two formulae for working out equivalent capacitance:Two capacitors in parallelThe equivalent single capacitance is the sum of the two capacitors: Ce = C1 + C2Two capacitors in seriesThe equivalent single capacitance is the reciprocal of the sum of the reciprocals of the two capacitors: 1/Ce = 1/C1 + 1/C2⇒ Ce = C1C2/(C1+C2)So you can replace two capacitors by a single one, or a single one by two.

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      Not sure what you are asking.There are two formulae for working out equivalent capacitance:Two capacitors in parallelThe equivalent single capacitance is the sum of the two capacitors: Ce = C1 + C2Two capacitors in seriesThe equivalent single capacitance is the reciprocal of the sum of the reciprocals of the two capacitors: 1/Ce = 1/C1 + 1/C2⇒ Ce = C1C2/(C1+C2)So you can replace two capacitors by a single one, or a single one by two.

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