math.answers.com/math-and-arithmetic/Chi-square_test_of_independence

Preview meta tags from the math.answers.com website.

Linked Hostnames

9

Thumbnail

Search Engine Appearance

Google

https://math.answers.com/math-and-arithmetic/Chi-square_test_of_independence

Chi-square test of independence? - Answers

This tests whether two categorical variables are related, meaning if they affect each (whether they are independent or associated. Your null hypothesis would be that these two variables are independent. Your alternate hypothesis would be that these two variables are dependent. To carry out this test, you must make sure that all the expected counts are greater than 1 and that 80% of these data are greater than 5. Moreover, you must make sure that the data was received by SRS and that the sample is independent. Afterwards, you can plug it in to your graphing calculator in a matrix and use the x^2test. However, if you do not have a graphing calculator, you must calculator the expected value of each value. You do this by multiplying the total counts in the row * total counts in the column/ total counts. Then for each value, you take: (Observed - Expected)^2 / (Expected). After you receive different values, you add them up to make up your x^2. Afterwards, you find the P-Value but looking at a chi distribution curve/table and find the area that is greater than x^2 value. If it is small, you can reject the null hypothesis (like less than 0.05). If not, you fail to reject the null hypothesis and therefore conclude that these two variables are independent.



Bing

Chi-square test of independence? - Answers

https://math.answers.com/math-and-arithmetic/Chi-square_test_of_independence

This tests whether two categorical variables are related, meaning if they affect each (whether they are independent or associated. Your null hypothesis would be that these two variables are independent. Your alternate hypothesis would be that these two variables are dependent. To carry out this test, you must make sure that all the expected counts are greater than 1 and that 80% of these data are greater than 5. Moreover, you must make sure that the data was received by SRS and that the sample is independent. Afterwards, you can plug it in to your graphing calculator in a matrix and use the x^2test. However, if you do not have a graphing calculator, you must calculator the expected value of each value. You do this by multiplying the total counts in the row * total counts in the column/ total counts. Then for each value, you take: (Observed - Expected)^2 / (Expected). After you receive different values, you add them up to make up your x^2. Afterwards, you find the P-Value but looking at a chi distribution curve/table and find the area that is greater than x^2 value. If it is small, you can reject the null hypothesis (like less than 0.05). If not, you fail to reject the null hypothesis and therefore conclude that these two variables are independent.



DuckDuckGo

https://math.answers.com/math-and-arithmetic/Chi-square_test_of_independence

Chi-square test of independence? - Answers

This tests whether two categorical variables are related, meaning if they affect each (whether they are independent or associated. Your null hypothesis would be that these two variables are independent. Your alternate hypothesis would be that these two variables are dependent. To carry out this test, you must make sure that all the expected counts are greater than 1 and that 80% of these data are greater than 5. Moreover, you must make sure that the data was received by SRS and that the sample is independent. Afterwards, you can plug it in to your graphing calculator in a matrix and use the x^2test. However, if you do not have a graphing calculator, you must calculator the expected value of each value. You do this by multiplying the total counts in the row * total counts in the column/ total counts. Then for each value, you take: (Observed - Expected)^2 / (Expected). After you receive different values, you add them up to make up your x^2. Afterwards, you find the P-Value but looking at a chi distribution curve/table and find the area that is greater than x^2 value. If it is small, you can reject the null hypothesis (like less than 0.05). If not, you fail to reject the null hypothesis and therefore conclude that these two variables are independent.

  • General Meta Tags

    22
    • title
      Chi-square test of independence? - Answers
    • charset
      utf-8
    • Content-Type
      text/html; charset=utf-8
    • viewport
      minimum-scale=1, initial-scale=1, width=device-width, shrink-to-fit=no
    • X-UA-Compatible
      IE=edge,chrome=1
  • Open Graph Meta Tags

    7
    • og:image
      https://st.answers.com/html_test_assets/Answers_Blue.jpeg
    • og:image:width
      900
    • og:image:height
      900
    • og:site_name
      Answers
    • og:description
      This tests whether two categorical variables are related, meaning if they affect each (whether they are independent or associated. Your null hypothesis would be that these two variables are independent. Your alternate hypothesis would be that these two variables are dependent. To carry out this test, you must make sure that all the expected counts are greater than 1 and that 80% of these data are greater than 5. Moreover, you must make sure that the data was received by SRS and that the sample is independent. Afterwards, you can plug it in to your graphing calculator in a matrix and use the x^2test. However, if you do not have a graphing calculator, you must calculator the expected value of each value. You do this by multiplying the total counts in the row * total counts in the column/ total counts. Then for each value, you take: (Observed - Expected)^2 / (Expected). After you receive different values, you add them up to make up your x^2. Afterwards, you find the P-Value but looking at a chi distribution curve/table and find the area that is greater than x^2 value. If it is small, you can reject the null hypothesis (like less than 0.05). If not, you fail to reject the null hypothesis and therefore conclude that these two variables are independent.
  • Twitter Meta Tags

    1
    • twitter:card
      summary_large_image
  • Link Tags

    16
    • alternate
      https://www.answers.com/feed.rss
    • apple-touch-icon
      /icons/180x180.png
    • canonical
      https://math.answers.com/math-and-arithmetic/Chi-square_test_of_independence
    • icon
      /favicon.svg
    • icon
      /icons/16x16.png

Links

58