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Could the average of three numbers be one of those three numbers? - Answers

Their are two cases when this might occur. Case 1: The three numbers you have are all the same number. This is pretty self exlanatory... but ill show an example 99+99+99/3=99 35+35+35/3=35 1056+1056+1056/3=1056 Case 2: You have one number that is exactly in the center of two other numbers. In other words this means that you have one number lets call it X then another number lets call it Y is a certain amount of units above number X. Then you have another number lets called this Z that is the same amount of units below X. Let me show you a few examples. 34+40+46/3 = 40 (In this case Z and Y are 6 units above and below X) 98+136+174/3 = 136 (In this case Z and Y are 38 units above and below X)



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Could the average of three numbers be one of those three numbers? - Answers

https://math.answers.com/math-and-arithmetic/Could_the_average_of_three_numbers_be_one_of_those_three_numbers

Their are two cases when this might occur. Case 1: The three numbers you have are all the same number. This is pretty self exlanatory... but ill show an example 99+99+99/3=99 35+35+35/3=35 1056+1056+1056/3=1056 Case 2: You have one number that is exactly in the center of two other numbers. In other words this means that you have one number lets call it X then another number lets call it Y is a certain amount of units above number X. Then you have another number lets called this Z that is the same amount of units below X. Let me show you a few examples. 34+40+46/3 = 40 (In this case Z and Y are 6 units above and below X) 98+136+174/3 = 136 (In this case Z and Y are 38 units above and below X)



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https://math.answers.com/math-and-arithmetic/Could_the_average_of_three_numbers_be_one_of_those_three_numbers

Could the average of three numbers be one of those three numbers? - Answers

Their are two cases when this might occur. Case 1: The three numbers you have are all the same number. This is pretty self exlanatory... but ill show an example 99+99+99/3=99 35+35+35/3=35 1056+1056+1056/3=1056 Case 2: You have one number that is exactly in the center of two other numbers. In other words this means that you have one number lets call it X then another number lets call it Y is a certain amount of units above number X. Then you have another number lets called this Z that is the same amount of units below X. Let me show you a few examples. 34+40+46/3 = 40 (In this case Z and Y are 6 units above and below X) 98+136+174/3 = 136 (In this case Z and Y are 38 units above and below X)

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      Their are two cases when this might occur. Case 1: The three numbers you have are all the same number. This is pretty self exlanatory... but ill show an example 99+99+99/3=99 35+35+35/3=35 1056+1056+1056/3=1056 Case 2: You have one number that is exactly in the center of two other numbers. In other words this means that you have one number lets call it X then another number lets call it Y is a certain amount of units above number X. Then you have another number lets called this Z that is the same amount of units below X. Let me show you a few examples. 34+40+46/3 = 40 (In this case Z and Y are 6 units above and below X) 98+136+174/3 = 136 (In this case Z and Y are 38 units above and below X)

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