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Could the segments 6 5 and 8 build a triangle? - Answers

To determine if segments of lengths 6, 5, and 8 can form a triangle, we can use the triangle inequality theorem. This theorem states that the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 6 + 5 = 11, which is greater than 8; 6 + 8 = 14, which is greater than 5; and 5 + 8 = 13, which is greater than 6. Since all conditions are satisfied, the segments can indeed form a triangle.



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Could the segments 6 5 and 8 build a triangle? - Answers

https://math.answers.com/math-and-arithmetic/Could_the_segments_6_5_and_8_build_a_triangle

To determine if segments of lengths 6, 5, and 8 can form a triangle, we can use the triangle inequality theorem. This theorem states that the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 6 + 5 = 11, which is greater than 8; 6 + 8 = 14, which is greater than 5; and 5 + 8 = 13, which is greater than 6. Since all conditions are satisfied, the segments can indeed form a triangle.



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https://math.answers.com/math-and-arithmetic/Could_the_segments_6_5_and_8_build_a_triangle

Could the segments 6 5 and 8 build a triangle? - Answers

To determine if segments of lengths 6, 5, and 8 can form a triangle, we can use the triangle inequality theorem. This theorem states that the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 6 + 5 = 11, which is greater than 8; 6 + 8 = 14, which is greater than 5; and 5 + 8 = 13, which is greater than 6. Since all conditions are satisfied, the segments can indeed form a triangle.

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      To determine if segments of lengths 6, 5, and 8 can form a triangle, we can use the triangle inequality theorem. This theorem states that the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 6 + 5 = 11, which is greater than 8; 6 + 8 = 14, which is greater than 5; and 5 + 8 = 13, which is greater than 6. Since all conditions are satisfied, the segments can indeed form a triangle.

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