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Explain how to factorize 2x squared plus 7x plus 6? - Answers

Your equation is a trimonial (made up of 3 parts) so your equation will end up being two sets of parentheses. In the first parentheses at the beginning goes the 2x, and at the begining of the second parentheses is x (because when you multiply 2x by x you get 2x^2 (two x squared) next you need to find two numbers that multiply to get six and also when you add them together you get seven. However since the beginning number is 2 (from the 2x) one of those two numbers has to be multiplied by 2 in order to get seven. The numbers needed are 2 and 3 with the two being the one that is multiplied by two. Therefore the second two needs to be i the second paretheses and the three needs to be in the first. Your equation will end up looking like this: (2x+3)(x+2)



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Explain how to factorize 2x squared plus 7x plus 6? - Answers

https://math.answers.com/math-and-arithmetic/Explain_how_to_factorize_2x_squared_plus_7x_plus_6

Your equation is a trimonial (made up of 3 parts) so your equation will end up being two sets of parentheses. In the first parentheses at the beginning goes the 2x, and at the begining of the second parentheses is x (because when you multiply 2x by x you get 2x^2 (two x squared) next you need to find two numbers that multiply to get six and also when you add them together you get seven. However since the beginning number is 2 (from the 2x) one of those two numbers has to be multiplied by 2 in order to get seven. The numbers needed are 2 and 3 with the two being the one that is multiplied by two. Therefore the second two needs to be i the second paretheses and the three needs to be in the first. Your equation will end up looking like this: (2x+3)(x+2)



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https://math.answers.com/math-and-arithmetic/Explain_how_to_factorize_2x_squared_plus_7x_plus_6

Explain how to factorize 2x squared plus 7x plus 6? - Answers

Your equation is a trimonial (made up of 3 parts) so your equation will end up being two sets of parentheses. In the first parentheses at the beginning goes the 2x, and at the begining of the second parentheses is x (because when you multiply 2x by x you get 2x^2 (two x squared) next you need to find two numbers that multiply to get six and also when you add them together you get seven. However since the beginning number is 2 (from the 2x) one of those two numbers has to be multiplied by 2 in order to get seven. The numbers needed are 2 and 3 with the two being the one that is multiplied by two. Therefore the second two needs to be i the second paretheses and the three needs to be in the first. Your equation will end up looking like this: (2x+3)(x+2)

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      Your equation is a trimonial (made up of 3 parts) so your equation will end up being two sets of parentheses. In the first parentheses at the beginning goes the 2x, and at the begining of the second parentheses is x (because when you multiply 2x by x you get 2x^2 (two x squared) next you need to find two numbers that multiply to get six and also when you add them together you get seven. However since the beginning number is 2 (from the 2x) one of those two numbers has to be multiplied by 2 in order to get seven. The numbers needed are 2 and 3 with the two being the one that is multiplied by two. Therefore the second two needs to be i the second paretheses and the three needs to be in the first. Your equation will end up looking like this: (2x+3)(x+2)
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