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Factor 7x2 plus 33x-10? - Answers
7(x^2)+33x-10 This is the way I would approach this problem. Find the factors of the first and last number: Factors of 7: 1,7 Factors of -10: -10,-5,-2,-1,1,2,5,10 Set up the two quantities: (x +/- __)(7x +/- __ ) Figure out which factors of -10 when multiplied with the factors of 7 then added together will equal +33: 5(7)+(-2)=33 Therefore: (x+5)(7x-2) Double check answer by foiling: (x+5)(7x-2)=7(x^2)-2x+35x-10 7(x^2)+33x-10
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Factor 7x2 plus 33x-10? - Answers
7(x^2)+33x-10 This is the way I would approach this problem. Find the factors of the first and last number: Factors of 7: 1,7 Factors of -10: -10,-5,-2,-1,1,2,5,10 Set up the two quantities: (x +/- __)(7x +/- __ ) Figure out which factors of -10 when multiplied with the factors of 7 then added together will equal +33: 5(7)+(-2)=33 Therefore: (x+5)(7x-2) Double check answer by foiling: (x+5)(7x-2)=7(x^2)-2x+35x-10 7(x^2)+33x-10
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Factor 7x2 plus 33x-10? - Answers
7(x^2)+33x-10 This is the way I would approach this problem. Find the factors of the first and last number: Factors of 7: 1,7 Factors of -10: -10,-5,-2,-1,1,2,5,10 Set up the two quantities: (x +/- __)(7x +/- __ ) Figure out which factors of -10 when multiplied with the factors of 7 then added together will equal +33: 5(7)+(-2)=33 Therefore: (x+5)(7x-2) Double check answer by foiling: (x+5)(7x-2)=7(x^2)-2x+35x-10 7(x^2)+33x-10
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