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Factor x squared plus 35x plus 216? - Answers
For this problem, you may want to use the quadratic formula:x = (-b +or- sqrt(b2-4ac))/(2a)where a and b are the coefficients in front of the x2 and x terms, and c is the constant term.In this case,a = 1b = 35c = 216Now simply plug these values into the quadratic formula stated above.x = (-35 +or- sqrt(352-4*1*216)) / (2*1)x = {-8, -27}These are the zeros of the function, so we can rewrite the expression given as(x + 8)(x + 27)Plug the two calculated values of x into the equation above and you will see that the expression is 0 at both points. To check if this is the correct answer, try expanding and see if it matches the original expression.
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Factor x squared plus 35x plus 216? - Answers
For this problem, you may want to use the quadratic formula:x = (-b +or- sqrt(b2-4ac))/(2a)where a and b are the coefficients in front of the x2 and x terms, and c is the constant term.In this case,a = 1b = 35c = 216Now simply plug these values into the quadratic formula stated above.x = (-35 +or- sqrt(352-4*1*216)) / (2*1)x = {-8, -27}These are the zeros of the function, so we can rewrite the expression given as(x + 8)(x + 27)Plug the two calculated values of x into the equation above and you will see that the expression is 0 at both points. To check if this is the correct answer, try expanding and see if it matches the original expression.
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Factor x squared plus 35x plus 216? - Answers
For this problem, you may want to use the quadratic formula:x = (-b +or- sqrt(b2-4ac))/(2a)where a and b are the coefficients in front of the x2 and x terms, and c is the constant term.In this case,a = 1b = 35c = 216Now simply plug these values into the quadratic formula stated above.x = (-35 +or- sqrt(352-4*1*216)) / (2*1)x = {-8, -27}These are the zeros of the function, so we can rewrite the expression given as(x + 8)(x + 27)Plug the two calculated values of x into the equation above and you will see that the expression is 0 at both points. To check if this is the correct answer, try expanding and see if it matches the original expression.
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