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https://math.answers.com/math-and-arithmetic/Factorise_2x_to_the_power_2_-18

Factorise 2x to the power 2 -18? - Answers

2x² - 18 Looking at it, you know that the first factors in each set are 2x and x. (2x ± ?) (x ± ?) Then guess and check to find 2 factors that when multipled together equal -18, but when plugged into the equation make the original statement true. In this case 6 and 3, however one or the other needs to be negative. (2x + 6)(x - 3) OR (2x - 6)(x + 3) Multiply it out to check your answer: (2x + 6)(x - 3) = 2x² - 6x + 6x - 18 2x² - 6x + 6x - 18 = 2x² - 18 You would get the same result with (2x - 6)(x + 3)



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Factorise 2x to the power 2 -18? - Answers

https://math.answers.com/math-and-arithmetic/Factorise_2x_to_the_power_2_-18

2x² - 18 Looking at it, you know that the first factors in each set are 2x and x. (2x ± ?) (x ± ?) Then guess and check to find 2 factors that when multipled together equal -18, but when plugged into the equation make the original statement true. In this case 6 and 3, however one or the other needs to be negative. (2x + 6)(x - 3) OR (2x - 6)(x + 3) Multiply it out to check your answer: (2x + 6)(x - 3) = 2x² - 6x + 6x - 18 2x² - 6x + 6x - 18 = 2x² - 18 You would get the same result with (2x - 6)(x + 3)



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https://math.answers.com/math-and-arithmetic/Factorise_2x_to_the_power_2_-18

Factorise 2x to the power 2 -18? - Answers

2x² - 18 Looking at it, you know that the first factors in each set are 2x and x. (2x ± ?) (x ± ?) Then guess and check to find 2 factors that when multipled together equal -18, but when plugged into the equation make the original statement true. In this case 6 and 3, however one or the other needs to be negative. (2x + 6)(x - 3) OR (2x - 6)(x + 3) Multiply it out to check your answer: (2x + 6)(x - 3) = 2x² - 6x + 6x - 18 2x² - 6x + 6x - 18 = 2x² - 18 You would get the same result with (2x - 6)(x + 3)

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      2x² - 18 Looking at it, you know that the first factors in each set are 2x and x. (2x ± ?) (x ± ?) Then guess and check to find 2 factors that when multipled together equal -18, but when plugged into the equation make the original statement true. In this case 6 and 3, however one or the other needs to be negative. (2x + 6)(x - 3) OR (2x - 6)(x + 3) Multiply it out to check your answer: (2x + 6)(x - 3) = 2x² - 6x + 6x - 18 2x² - 6x + 6x - 18 = 2x² - 18 You would get the same result with (2x - 6)(x + 3)

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