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Find domain and range of f x x 2 plus 1? - Answers

The function ( f(x) = x^2 + 1 ) is a quadratic function. The domain is all real numbers, expressed as ( (-\infty, \infty) ), since you can input any real number for ( x ). The range is ( [1, \infty) ) because the minimum value of the function occurs at ( x = 0 ), where ( f(0) = 1 ), and the function increases without bound as ( x ) moves away from zero.



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Find domain and range of f x x 2 plus 1? - Answers

https://math.answers.com/math-and-arithmetic/Find_domain_and_range_of_f_x_x_2_plus_1

The function ( f(x) = x^2 + 1 ) is a quadratic function. The domain is all real numbers, expressed as ( (-\infty, \infty) ), since you can input any real number for ( x ). The range is ( [1, \infty) ) because the minimum value of the function occurs at ( x = 0 ), where ( f(0) = 1 ), and the function increases without bound as ( x ) moves away from zero.



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https://math.answers.com/math-and-arithmetic/Find_domain_and_range_of_f_x_x_2_plus_1

Find domain and range of f x x 2 plus 1? - Answers

The function ( f(x) = x^2 + 1 ) is a quadratic function. The domain is all real numbers, expressed as ( (-\infty, \infty) ), since you can input any real number for ( x ). The range is ( [1, \infty) ) because the minimum value of the function occurs at ( x = 0 ), where ( f(0) = 1 ), and the function increases without bound as ( x ) moves away from zero.

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      The function ( f(x) = x^2 + 1 ) is a quadratic function. The domain is all real numbers, expressed as ( (-\infty, \infty) ), since you can input any real number for ( x ). The range is ( [1, \infty) ) because the minimum value of the function occurs at ( x = 0 ), where ( f(0) = 1 ), and the function increases without bound as ( x ) moves away from zero.

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