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Find the area of an equilateral triangle of side 10? - Answers

First find the perpendicular height (h) of the triangle using Pythagoras.h = sqrt (102 - 52) = sqrt 75 = 8.660254038...Now, area of a triangle = 1/2 base x height.So: area = 1/2 x 10 x 8.660254038 = 43.3 (1 decimal place.)



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Find the area of an equilateral triangle of side 10? - Answers

https://math.answers.com/math-and-arithmetic/Find_the_area_of_an_equilateral_triangle_of_side_10

First find the perpendicular height (h) of the triangle using Pythagoras.h = sqrt (102 - 52) = sqrt 75 = 8.660254038...Now, area of a triangle = 1/2 base x height.So: area = 1/2 x 10 x 8.660254038 = 43.3 (1 decimal place.)



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https://math.answers.com/math-and-arithmetic/Find_the_area_of_an_equilateral_triangle_of_side_10

Find the area of an equilateral triangle of side 10? - Answers

First find the perpendicular height (h) of the triangle using Pythagoras.h = sqrt (102 - 52) = sqrt 75 = 8.660254038...Now, area of a triangle = 1/2 base x height.So: area = 1/2 x 10 x 8.660254038 = 43.3 (1 decimal place.)

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      First find the perpendicular height (h) of the triangle using Pythagoras.h = sqrt (102 - 52) = sqrt 75 = 8.660254038...Now, area of a triangle = 1/2 base x height.So: area = 1/2 x 10 x 8.660254038 = 43.3 (1 decimal place.)

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