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Find the tangent of the curve 2x plus y equals 13? - Answers

This is not a curve, but a line. It's slope will always be the same then, and it does not have tangent. You can find it's rate of change easily enough though, that being it's slope. In this case, you can rewrite the equation as: y = 13 - 2x And you can see that it has a slope of negative two. This can be demonstrated as well by taking it's derivative: y = 13 - 2 * x1 ∴ y' = -2 * 1 * x1 - 1 ∴ y' = -2 * 1 * x0 ∴ y' = -2 * 1* 1 ∴ y' = -2



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Find the tangent of the curve 2x plus y equals 13? - Answers

https://math.answers.com/math-and-arithmetic/Find_the_tangent_of_the_curve_2x_plus_y_equals_13

This is not a curve, but a line. It's slope will always be the same then, and it does not have tangent. You can find it's rate of change easily enough though, that being it's slope. In this case, you can rewrite the equation as: y = 13 - 2x And you can see that it has a slope of negative two. This can be demonstrated as well by taking it's derivative: y = 13 - 2 * x1 ∴ y' = -2 * 1 * x1 - 1 ∴ y' = -2 * 1 * x0 ∴ y' = -2 * 1* 1 ∴ y' = -2



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https://math.answers.com/math-and-arithmetic/Find_the_tangent_of_the_curve_2x_plus_y_equals_13

Find the tangent of the curve 2x plus y equals 13? - Answers

This is not a curve, but a line. It's slope will always be the same then, and it does not have tangent. You can find it's rate of change easily enough though, that being it's slope. In this case, you can rewrite the equation as: y = 13 - 2x And you can see that it has a slope of negative two. This can be demonstrated as well by taking it's derivative: y = 13 - 2 * x1 ∴ y' = -2 * 1 * x1 - 1 ∴ y' = -2 * 1 * x0 ∴ y' = -2 * 1* 1 ∴ y' = -2

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      This is not a curve, but a line. It's slope will always be the same then, and it does not have tangent. You can find it's rate of change easily enough though, that being it's slope. In this case, you can rewrite the equation as: y = 13 - 2x And you can see that it has a slope of negative two. This can be demonstrated as well by taking it's derivative: y = 13 - 2 * x1 ∴ y' = -2 * 1 * x1 - 1 ∴ y' = -2 * 1 * x0 ∴ y' = -2 * 1* 1 ∴ y' = -2

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