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Find the x-intercept of the graph of -5x plus 20y equals 20? - Answers

The x intercept is where y = 0, on the x-axis. So plug in y=0 to you equation:-5(x) + 20(0) = 20 ... -5(x) = 20...Divide each side by -5: x = 20/-5 = -20/5 = = -4.Therefore the x intercept is where y = 0 and x = -4 --> (-4, 0)Send any math questions to me for answering!



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Find the x-intercept of the graph of -5x plus 20y equals 20? - Answers

https://math.answers.com/math-and-arithmetic/Find_the_x-intercept_of_the_graph_of_-5x_plus_20y_equals_20

The x intercept is where y = 0, on the x-axis. So plug in y=0 to you equation:-5(x) + 20(0) = 20 ... -5(x) = 20...Divide each side by -5: x = 20/-5 = -20/5 = = -4.Therefore the x intercept is where y = 0 and x = -4 --> (-4, 0)Send any math questions to me for answering!



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https://math.answers.com/math-and-arithmetic/Find_the_x-intercept_of_the_graph_of_-5x_plus_20y_equals_20

Find the x-intercept of the graph of -5x plus 20y equals 20? - Answers

The x intercept is where y = 0, on the x-axis. So plug in y=0 to you equation:-5(x) + 20(0) = 20 ... -5(x) = 20...Divide each side by -5: x = 20/-5 = -20/5 = = -4.Therefore the x intercept is where y = 0 and x = -4 --> (-4, 0)Send any math questions to me for answering!

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      The x intercept is where y = 0, on the x-axis. So plug in y=0 to you equation:-5(x) + 20(0) = 20 ... -5(x) = 20...Divide each side by -5: x = 20/-5 = -20/5 = = -4.Therefore the x intercept is where y = 0 and x = -4 --> (-4, 0)Send any math questions to me for answering!

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