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Find three consecutive integers whose sum exceeds the smallest integer by 51? - Answers

First we need to understand that consecutive integers means integers such that each one is 1 bigger than the one before it. So 3 and 4 are consecutive.Now if we let x be the first integer. The next is 1 bigger so it is x+1 and the third is 1 bigger than the second so it is x+2.Now we are told the sum if 51 greater than the smallest number.so we have x+x+1+x+2=3x+3=SumBut we know that sum is 51 greater than x, so we write3x+3=x+51Solving we find:2x=48and x=24.So the numbers are24,25, and 26.The sum is 75 which is 51 more than 24 so we are done.



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Find three consecutive integers whose sum exceeds the smallest integer by 51? - Answers

https://math.answers.com/math-and-arithmetic/Find_three_consecutive_integers_whose_sum_exceeds_the_smallest_integer_by_51

First we need to understand that consecutive integers means integers such that each one is 1 bigger than the one before it. So 3 and 4 are consecutive.Now if we let x be the first integer. The next is 1 bigger so it is x+1 and the third is 1 bigger than the second so it is x+2.Now we are told the sum if 51 greater than the smallest number.so we have x+x+1+x+2=3x+3=SumBut we know that sum is 51 greater than x, so we write3x+3=x+51Solving we find:2x=48and x=24.So the numbers are24,25, and 26.The sum is 75 which is 51 more than 24 so we are done.



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https://math.answers.com/math-and-arithmetic/Find_three_consecutive_integers_whose_sum_exceeds_the_smallest_integer_by_51

Find three consecutive integers whose sum exceeds the smallest integer by 51? - Answers

First we need to understand that consecutive integers means integers such that each one is 1 bigger than the one before it. So 3 and 4 are consecutive.Now if we let x be the first integer. The next is 1 bigger so it is x+1 and the third is 1 bigger than the second so it is x+2.Now we are told the sum if 51 greater than the smallest number.so we have x+x+1+x+2=3x+3=SumBut we know that sum is 51 greater than x, so we write3x+3=x+51Solving we find:2x=48and x=24.So the numbers are24,25, and 26.The sum is 75 which is 51 more than 24 so we are done.

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      First we need to understand that consecutive integers means integers such that each one is 1 bigger than the one before it. So 3 and 4 are consecutive.Now if we let x be the first integer. The next is 1 bigger so it is x+1 and the third is 1 bigger than the second so it is x+2.Now we are told the sum if 51 greater than the smallest number.so we have x+x+1+x+2=3x+3=SumBut we know that sum is 51 greater than x, so we write3x+3=x+51Solving we find:2x=48and x=24.So the numbers are24,25, and 26.The sum is 75 which is 51 more than 24 so we are done.

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