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Find two numbers whose sum is 48 and whose difference is 26? - Answers
Two ways to do this: x + y = 48 y = 48-x x - y = 26 x - 48 + x = 26 2x = 74 x = 37 y = 48-37 = 11 so 37 and 11 Other method x + y=48 x - y=26 Subtract line 1 from line 2 2y = 22 y = 11 then solve for x x +11=48 x = 37 again you get 37 and 11
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Find two numbers whose sum is 48 and whose difference is 26? - Answers
Two ways to do this: x + y = 48 y = 48-x x - y = 26 x - 48 + x = 26 2x = 74 x = 37 y = 48-37 = 11 so 37 and 11 Other method x + y=48 x - y=26 Subtract line 1 from line 2 2y = 22 y = 11 then solve for x x +11=48 x = 37 again you get 37 and 11
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Find two numbers whose sum is 48 and whose difference is 26? - Answers
Two ways to do this: x + y = 48 y = 48-x x - y = 26 x - 48 + x = 26 2x = 74 x = 37 y = 48-37 = 11 so 37 and 11 Other method x + y=48 x - y=26 Subtract line 1 from line 2 2y = 22 y = 11 then solve for x x +11=48 x = 37 again you get 37 and 11
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- og:descriptionTwo ways to do this: x + y = 48 y = 48-x x - y = 26 x - 48 + x = 26 2x = 74 x = 37 y = 48-37 = 11 so 37 and 11 Other method x + y=48 x - y=26 Subtract line 1 from line 2 2y = 22 y = 11 then solve for x x +11=48 x = 37 again you get 37 and 11
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